The beakers on the left and right both contain the same amount of HCL (liquid) and the same mass of calcium carbonate (solid). I
n which beaker will the reaction rate be the greatest?
A) The reaction rate will be highest in beaker 1 because there is a larger surface area of calcium carbonate.
B) The reaction rate will be highest in beaker 2 because there is a larger surface area of calcium carbonate.
C) The reaction rate will be highest in beaker 1 because there is a smaller surface area of calcium carbonate.
D) The reaction rate will be highest in beaker 2 because there is a smaller surface area of calcium carbonate
A) The reaction rate will be highest in beaker 1 because there is a larger surface area of calcium carbonate.
B) The reaction rate will be highest in beaker 2 because there is a larger surface area of calcium carbonate.
C) The reaction rate will be highest in beaker 1 because there is a smaller surface area of calcium carbonate.
D) The reaction rate will be highest in beaker 2 because there is a smaller surface area of calcium carbonate
1 answer:
You might be interested in
Explanation:
The chemical equation is as follows.
And, the given enthalpy is as follows.
;
= 102.5 kJ
Cl-Cl = 243 kJ/mol, O=O = 498 kJ/mol
Since, the bond enthalpy of Cl-Cl is not given so at first, we will calculate the value of Cl-Cl as follows.
102.5 =
102.5 =
102.5 - 12 =
x = 181 kJ
Now, total bond enthalpy of per mole of ClO is calculated as follows.
x =
= 339.5 - 243
= 96.5 kJ
Thus, we can conclude that the value for the enthalpy of formation per mole of ClO(g) is 96.5 kJ.