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nata0808 [166]
2 years ago
7

The beakers on the left and right both contain the same amount of HCL (liquid) and the same mass of calcium carbonate (solid). I

n which beaker will the reaction rate be the greatest?
A) The reaction rate will be highest in beaker 1 because there is a larger surface area of calcium carbonate.

B) The reaction rate will be highest in beaker 2 because there is a larger surface area of calcium carbonate.

C) The reaction rate will be highest in beaker 1 because there is a smaller surface area of calcium carbonate.

D) The reaction rate will be highest in beaker 2 because there is a smaller surface area of calcium carbonate

Chemistry
1 answer:
ruslelena [56]2 years ago
7 0

Answer:

B

Explanation:

Smaller pieces results in a larger surface area, therefore the answer is beaker B.

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b) a rubber tire

Explanation:

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Calculate the Ka for the following acid. Determine if it is a strong or weak acid.
vladimir1956 [14]

Answer:

a) Ka= 7.1 × 10⁻⁴; This is a weak acid because the acid is not completely dissociated in solution.

Explanation:

Step 1: Write the dissociation reaction for nitrous acid

HNO₂(aq) ⇄ H⁺(aq) and NO₂⁻(aq)

Step 2: Calculate the acid dissociation constant

Ka = [H⁺] × [NO₂⁻] / [HNO₂]

Ka = 0.022 × 0.022 / 0.68

Ka = 7.1 × 10⁻⁴

Step 3: Determine the strength of the acid

Since Ka is very small, nitrous acid is a weak acid, not completely dissociated in solution.

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Which representative element has the largest atomic radius ?
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francium

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the atomic radius increases from top to bottom in a group, and decreases from left to right across a period.

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What is the reaction between aspirin and hydrochloric acid
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Balance the equation :
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The balanced equation is 2 AlI 3 ( a q ) + 3 Cl 2 ( g ) → 2 AlCl 3 ( a q ) + 3 I 2 ( g ) .

<u>Explanation:</u>

  • Aluminum has a typical oxidation condition of  3+  , and that of iodine is  1-  .   Along these lines, three iodides can bond with one aluminum. You get  AlI3.  For comparable reasons, aluminum chloride is  AlCl3.  
  • Chlorine and iodine both exist normally as diatomic components, so they are  Cl2(  g  )  also,  I2(  g  ), individually. In spite of the fact that I would anticipate that iodine should be a strong.  

Balancing the equation, we get:  

            2AlI 3(  aq  )  +  3Cl2 (  g  )  →  2AlCl3 (  aq  )   +  3 I 2  (  g  )  

  • Realizing that there were two chlorines on the left, I simply found the basic numerous of 2 and 3 to be 6, and multiplied the  AlCl  3  on the right.  
  • Normally, presently we have two  Al  on the right, so I multiplied the  AlI  3  on the left. Hence, I have 6  I  on the left, and I needed to significantly increase  I 2  on the right.  
  • We should note, however, that aluminum iodide is viciously receptive in water except if it's a hexahydrate. In this way, it's most likely the anhydrous adaptation broke down in water, and the measure of warmth created may clarify why iodine is a vaporous item, and not a strong.
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