I think the answer is:
B. Chemical Change.
Reduction
half reaction
2H_2O
+ CrO_4^2- + 3e -> CrO_2^- + 4OH^-
Oxidation
half reaction
2OH^-
+ SO_3^2- -> SO_4^2- + H_2O + 2e
Balanced
overall equation
H_2O
+ 2CrO_4^2- + 3SO_3^2- -> 3SO_3^2- + 2CrO_2^- + 2OH^-
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Answer: The oxidation state of selenium in SeO3 is +6
Explanation:
SeO3 is the chemical formula for selenium trioxide.
- The oxidation state of SeO3 = 0 (since it is stable and with no charge)
- the oxidation number of oxygen (O) IN SeO3 is -2
- the oxidation state of selenium in SeO3 = Z (let unknown value be Z)
Hence, SeO3 = 0
Z + (-2 x 3) = 0
Z + (-6) = 0
Z - 6 = 0
Z = 0 + 6
Z = +6
Thus, the oxidation state of selenium in SeO3 is +6
Answer:
Sugar (Sucrose), Corn Syrup (Glucose), Molasses (C6H12NNaO3S)
Explanation:
Each of these is a sweetener.
244.4 degrees farenheit. (118 degrees celsius)