Atmospheric pressure decreases with the increase in altitude.
hope that helps you!
Answer:
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Answer:
mj = 53.3kg
Explanation:
Since both gravitational energies are the same:
Eb = Ej => mb*g*hb = mj*g*hj
Solving for mj:
mj = mb*hb/hj = 80*2.4/3.6
mj = 53.3kg
Answer:
t = √2y/g
Explanation:
This is a projectile launch exercise
a) The vertical velocity in the initial instants (
= 0) zero, so let's use the equation
y =
t -1/2 g t²
y= - ½ g t²
t = √2y/g
b) Let's use this time and the horizontal displacement equation, because the constant horizontal velocity
x = vox t
x = v₀ₓ √2y/g
c) Speeds before touching the ground
vₓ = vox = constant
=
- gt
= 0 - g √2y/g
= - √2gy
tan θ = Vy / vx
θ = tan⁻¹ (vy / vx)
θ = tan⁻¹ (√2gy / vox)
d) The projectile is higher than the cliff because it is a horizontal launch