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Anuta_ua [19.1K]

3 years ago

10

A block is hung by two ropes angled at 30º and 60º respectively. What is the ratio of the tension in the second rope to the tens

ion in the first rope?

1 answer:

WINSTONCH [101]3 years ago

8 0

The ratio between 30° and 60° is 1:2

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Compared to Jupiter, Saturn's atmosphere is more uniform with no significant variation in color in the lower cloud levels. much

creativ13 [48]

Answer:

Explained

Explanation:

Compared to Jupiter, Saturn's atmosphere is more calm with fewer disturbances or storms.

The Atmosphere in Jupiter is highly violent and thinner as compared with Saturn.

The layers of atmosphere on Saturn is thicker because of lower gravity of Saturn and hence they are calmer.

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2 years ago

The coefficient of static friction between a 3.00 kg crate and the 35.0o incline is 0.300. What minimum force F must be applied

Yakvenalex [24]

Answer:

So the minimum force is

32.2Newton

Explanation:

To solve for the minimum force, let us assume it to be F (N)

So

F=mgsinA

But

=>>>> coefficient of static friction x (F + mgcosA

=>3 x 9.8 x sin35 = 0.3 x (F + 3 x 9.8 x cos35)

So making F subject of formula

F + 24.0 = 56.2

F = 32.2N

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2 years ago

Which best describes the way a sound wave is sent trough the radio?

horsena [70]

Sound wave > electric signal > radio wave > sound wave

4 0

2 years ago

Read 2 more answers

A motorcycle, which has an initial linear speed of 9.7 m/s, decelerates to a speed of 4.0 m/s in 4.4 s. Each wheel has a radius

Morgarella [4.7K]

Hi there!

We can begin by solving for the linear acceleration as we are given sufficient values to do so.

We can use the following equation:

vf = vi + at

Plug in given values:

4 = 9.7 + 4.4a

Solve for a:

a = -1.295 m/s²

We can use the following equation to convert from linear to angular acceleration:

a = αr

a/r = α

Thus:

-1.295/0.61 = -2.124 rad/sec² ⇒ 2.124 rad/sec² since counterclockwise is positive.

Now, we can find the angular displacement using the following:

θ = ωit + 1/2αt²

We must convert the initial velocity of the tire (9.7 m/s) to angular velocity:

v = ωr

v/r = ω

9.7/0.61 = 15.9 rad/sec

Plug into the equation:

θ = 15.9(4.4) + 1/2(2.124)(4.4²) = 20.56 rad

6 0

2 years ago

A crash test dummy with a mass of 55kg is placed into a car traveling at 40m/s. During the first trial the dummy does not wear a

s2008m [1.1K]

a. The force experienced by the dummy with a seatbelt is 11,000 Newton.

b. The force experienced by the dummy without a seatbelt is 4,400 Newton.

<u>Given the following data:</u>

Mass = 55 kg

Initial velocity = 0 m/s

Final velocity = 40 m/s

Time A = 0.2 seconds

Time B = 0.5 seconds

a. To calculate the force experienced by the dummy with a seatbelt:

<h3>Newton's Second Law of Motion</h3>

In order to solve for the force acting on the dummy, we would apply Newton's Second Law of Motion.

<u>Note:</u> The acceleration of an object is equal to the rate of change in velocity with respect to time.

Mathematically, Newton's Second Law of Motion is given by this formula;

$F = \frac{M(v\;-\;u)}{t}$

Substituting the given parameters into the formula, we have;

$F = \frac{55(40\;-\;0)}{0.2}\\\\F = \frac{55\times 40}{0.2}\\\\F = \frac{2200}{0.2}$

Force = 11,000 Newton.

b. To calculate the force experienced by the dummy without a seatbelt:

$F = \frac{55(40\;-\;0)}{0.5}\\\\F = \frac{55\times 40}{0.5}\\\\F = \frac{2200}{0.5}$

Force = 4,400 Newton.

Read more on force here: brainly.com/question/1121817

4 0

2 years ago