We can solve for the length of side a to the nearest whole number using the Laws of Cosines such as the formula is shown below:
a²=b²+c²-2bcCosA
Solving for the value of a, we have:
a²=10²+14²-2(10)(14)cos54°
a²=131.42
a=11.46
The answer is 11.46 or 11.5.
The area is 14! hope this helps
Ok if the number behind the decimal is 4-0... round down, But if the number is 5-9 round up.
Example:65.85
The number behind the decimal is a 8.. So round this number up to the next availible whole number, which is 66.
Answer:
-4,-5
Step-by-step explanation:
Looking at the system of equations, I can't see any way to add the equations together to eliminate a variable. So, I decided to use substitution. First, I created 2 new equations, x = -24 - 4y and Y=2X+3 by rewriting each equation to solve for x and y. Now, I can take one of these equations and insert it in the opposite equation and solve for a variable.
4(-24 - 4y) - 2y = -6
-96 -16y -2y = -6
-18y = 90
y = -5
Now, I can just insert this in one of my equations and solve for x, and get my solution, which gets me x = -4
