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irinina [24]
3 years ago
14

Maureen takes notes in class. Wave Interactions

Physics
2 answers:
Monica [59]3 years ago
7 0
A. <span>I .................
</span>
m_a_m_a [10]3 years ago
5 0

Answer;

I

Explanation;

Wave interactions results from the interaction of waves and matter, these interactions occur when waves pass from one medium to another. The types of interactions includes; reflection, refraction, interference and diffraction.

  • Reflection takes place when waves bounce back from a surface that they cannot pass through.
  • Refraction takes place when waves bend as they enter a new medium at an angle and start traveling at a different speed.
  • Diffraction is another wave interaction that occur when waves spread out as they travel around obstacles or through openings in obstacles.
  • Interference occurs when two or more waves meet at the same place a the same time.
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A ferris wheel car with a mass of 350 kg, travels in a
SpyIntel [72]

Answer:Any force or combination of forces can cause a centripetal or radial acceleration. Just a few examples are the tension in the rope on a tether ball, the force of Earth’s gravity on the Moon, friction between roller skates and a rink floor, a banked roadway’s force on a car, and forces on the tube of a spinning centrifuge.

Any net force causing uniform circular motion is called a centripetal force. The direction of a centripetal force is toward the center of curvature, the same as the direction of centripetal acceleration. According to Newton’s second law of motion, net force is mass times acceleration: net F = ma. For uniform circular motion, the acceleration is the centripetal acceleration—a = ac. Thus, the magnitude of centripetal force Fc is Fc = mac.

By using the expressions for centripetal acceleration ac from  

a

c

=

v

2

r

;

a

c

=

r

ω

2

, we get two expressions for the centripetal force Fc in terms of mass, velocity, angular velocity, and radius of curvature:  

F

c

=

m

v

2

r

;

F

c

=

m

r

ω

2

.

You may use whichever expression for centripetal force is more convenient. Centripetal force Fc is always perpendicular to the path and pointing to the center of curvature, because ac is perpendicular to the velocity and pointing to the center of curvature.

Note that if you solve the first expression for r, you get  

r

=

m

v

2

F

c

.

This implies that for a given mass and velocity, a large centripetal force causes a small radius of curvature—that is, a tight curve.

The given figure consists of two semicircles, one over the other. The top semicircle is bigger and the one below is smaller. In both the figures, the direction of the path is given along the semicircle in the counter-clockwise direction. A point is shown on the path, where the radius from the circle, r, is shown with an arrow from the center of the circle. At the same point, the centripetal force is shown in the opposite direction to that of radius arrow. The velocity, v, is shown along this point in the left upward direction and is perpendicular to the force. In both the figures, the velocity is same, but the radius is smaller and centripetal force is larger in the lower figure.

Figure 1. The frictional force supplies the centripetal force and is numerically equal to it. Centripetal force is perpendicular to velocity and causes uniform circular motion. The larger the Fc, the smaller the radius of curvature r and the sharper the curve. The second curve has the same v, but a larger Fc produces a smaller r′.

Explanation:

6 0
3 years ago
A motorboat sets out for open sea. From home it travels 5 km due East, then heads [N35E] at 2 m/s for 90 minutes. After a break,
geniusboy [140]

The distance of the motorboat relative to the home, which travels in various directions, is 3.07 km.

<h3>What is relative velocity?</h3>

Relative velocity is a velocity of an object which is in respect to another observer, or it is a ratio of change in the position of a point to time with respect to another observer.

Given: Travel in East direction (d_{E})= 5 km,

velocity in N35E(v) = 2 m / s, time taken(t)  = 90 min = 5400 seconds,
Displacement in south (D_S}) = 6.5 km

Firstly, find the displacement  in N35E so

Displacement   = Velocity × time,

d_{NE} = 2 × 5400 = 10800 meters or 10.8 km

Now by using Pythagoras' theorem
We can calculate the return displacement in the south direction(d_{S}),

d_{S} = \sqrt{d^{2} _{NE}- d^{2} _{E }  }
d_{S} = \sqrt{10.8^{2}-5^{2}  }

d_{S} = 9.57 km

Therefore, the distance of the boat from the home (D) = d_S} - D_S}

D = 9.57 - 6.5;

D = 3.07 Km

To know more about Relative velocity:

brainly.com/question/19260269

#SPJ1

3 0
1 year ago
A battery has a difference in potential energy between the positive terminal and negative terminal. Which units express this dif
kow [346]
The correct answer among all the other choices is volts. This unit expresses the difference in energy. It is not watts or amps. Thank you for posting your question. I hope this answer helped you. Let me know if you need more help. 
5 0
3 years ago
You dribble a basketball while walking on a basketball court. List and describe at least 3
Airida [17]

Answer:

1. You push on the ball and the ball pushes on your hand .

2. The ball hits the ground and the ground pushes back on the ball .

3. You walk on the ground with your feet and the ground pushes back on you.

Explanation:

4 0
4 years ago
Read 2 more answers
Which term is defined as an elongated area of low pressure?
fenix001 [56]

Answer:

A trough

Explanation:

A trough is an elongated area of relatively low pressure extending from the center of a region of low pressure.

I HoPe ThIs Helps!!!

6 0
3 years ago
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