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2 years ago

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When 3.18g of copper(ii)oxide was carefully heated in a stream of dry hydrogen, 2.54g of copper and 0.72g of water was formed. D

etermine the number of moles of hydrogen atoms which combine with one mole of oxygen atoms. Show your working.

1 answer:

Klio2033 [76]2 years ago

7 0

Answer:

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The pH of an acidic solution is 2.11. What is [H⁺]

BartSMP [9]

Answer:

denotes the molar hydrogen ion concentration

Explanation:

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2 years ago

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What is the pH of a solution with [H+]=6.2x10-9 M?

Serga [27]

Answer: 8.2

Explanation:

pH of a solution is - Log [ H+].

pH = - Log [ 6.2 x 10-9 M]

= 9 - 0.7924

pH = 8.24 approx 8.2

3 0

3 years ago

Write the isotopic symbol for the following (show your work) a) An isotope of iodine whose atoms have 78 neutrons b) An isotope

morpeh [17]

<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

<u>For b:</u> The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

<u>For c:</u> The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

<u>Explanation:</u>

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

<u>For a:</u>

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

<u>For b:</u>

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

<u>For c:</u>

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

3 0

3 years ago

How many moles are there in 78.3g of CO2?

oksano4ka [1.4K]

The molar mass of CO2 can be calculated as follows;
CO2 — 12 + (16x2) = 12+ 32 = 44 g
Therefore molar mass of CO2 is 44 g/mol
In 44 g of CO2 there’s 1 mol of CO2
Then 1 g of CO2 there’s 1/44 mol of CO2
Therefore in 78.3 g of CO2 there’s — 1/44 x 78.3 =1.78 mol of CO2

4 0

3 years ago

The vapor pressure of pure acetone (C3H6O) is 216 torr

svetoff [14.1K]

The mole fraction of acetone (C₃H₆O) is 0.333

<h3>Data obtained from the question </h3>

Mole of C₃H₆O = 0.1 mole
Mole of CHCl₃ = 0.2 mole
Mole fraction of C₃H₆O =?

<h3>How to determine the mole fraction </h3>

Mole fraction of a substance can be obtained by using the following formula:

Mole fraction = mole / total mole

With the above formula, we can obtain the mole fraction of C₃H₆O as follow:

Mole of C₃H₆O = 0.1 mole
Mole of CHCl₃ = 0.2 mole
Total mole = 0.1 + 0.2 = 0.3 mole
Mole fraction of C₃H₆O =?

Mole fraction = mole / total mole

Mole fraction of C₃H₆O = 0.1 / 0.3

Mole fraction of C₃H₆O = 0.333

Learn more about mole fraction:

brainly.com/question/2769009

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2 years ago