Question

Help me please please

Answer 1

Answer:

Step-by-step explanation:

Number 2 first:

See the graph below for a hint. (Do you know how to use Desmos ?)

factoring seems to make no sense for $y =-x^{2} +2x +4$  but "guess and check" seems to work. I tried 4 for x, but that proved false. 3 for x made sense. You get $-3x^{2} +2(3) +4 =y$  so -9 +6 +4 = 1 is true.  So (3,1)

x+y=4 becomes 3 + 1 = 4  Also true

According to the graph, (0,4) would also be a solution, so (3,1) and (0,4)

Part 1:

Factor $x^{2} +4x +3$  as $(x + 3)(x + 1)$ set each equal to 0 and get

x = -3 and x = -1  so the solutions seem be (-3,0) and (-1,0)

y = 2x + 6  factors to 2(x +3)

(-1,0) doesn't work!

But Desmos shows something else as a solution set for both:

(1,8)

y=2x+6 substitute values 8=2(1) +6  8=2+6 True

y = $x^{2} +4x +3$. Substitute values  $8 =1^{2} +4(1) +3$  8= 1+4+3 True