Answer: T2 = 7.07s
Explanation: The period of a loaded spring of spring constant k and mass m is given by
T= 2π √m/k
With 2π constant and k, it can be seen with little algebra that
T² is proportional to mass m
Hence (T1)²/m1 = (T2) ²/m2
Where T1 = 5, T2 =?, let m1 = m hence m2 = 2m.
By substituting, we have that
5²/m = (T2) ²/2m
25 / m = (T2) ²/2m
25 × 2m = (T2) ² × m
25 × 2 = (T2) ²
50 = (T2) ²
T2 = √50
T2 = 7.07s
Answer:
what did u say and what language are you speaking in
Hi there!
We can use the rotational equivalent of Newton's Second Law:
Στ = Net Torque (Nm)
I = Moment of inertia (kgm²)
α = Angular acceleration (rad/sec²)
We can plug in the given values to solve.
Answer:
The activation energy for this reaction, Ea = 159.98 kJ/mol
Explanation:
Using the Arrhenius equation as:
Where, Ea is the activation energy.
R is the gas constant having value 8.314 J/K.mol
K₂ and K₁ are the rate constants
T₂ and T₁ are the temperature values in kelvin.
Given:
K₂ = 8.66×10⁻⁷ s⁻¹ , T₂ = 425 K
K₁ = 3.61×10⁻¹⁵ s⁻¹ , T₁ = 298 K
Applying in the equation as:
Solving for Ea as:
Ea = 159982.23 J /mol
1 J/mol = 10⁻³ kJ/mol
Ea = 159.98 kJ/mol
Answer:
the mass of water is 0.3 Kg
Explanation:
since the container is well-insulated, the heat released by the copper is absorbed by the water , therefore:
Q water + Q copper = Q surroundings =0 (insulated)
Q water = - Q copper
since Q = m * c * ( T eq - Ti ) , where m = mass, c = specific heat, T eq = equilibrium temperature and Ti = initial temperature
and denoting w as water and co as copper :
m w * c w * (T eq - Tiw) = - m co * c co * (T eq - Ti co) = m co * c co * (T co - Ti eq)
m w = m co * c co * (T co - Ti eq) / [ c w * (T eq - Tiw) ]
We take the specific heat of water as c= 1 cal/g °C = 4.186 J/g °C . Also the specific heat of copper can be found in tables → at 25°C c co = 0.385 J/g°C
if we assume that both specific heats do not change during the process (or the change is insignificant)
m w = m co * c co * (T eq - Ti co) / [ c w * (T eq - Tiw) ]
m w= 1.80 kg * 0.385 J/g°C ( 150°C - 70°C) /( 4.186 J/g°C ( 70°C- 27°C))
m w= 0.3 kg
