Answer:
120 J
Explanation:
KE = mv²/2 = (0.15 kg * [40 m/s]²)/2 = 120 J
B :)
:) JUST TRUST ME I GOT IT CORRECT
The answer is 904,000.
Kinetic energy=1/2mv^2.
1/2×1130×40^2.
1/2×1808000=904,000Joules.
The force per unit length between the two wires is
The magnitude of the force per unit length exerted between two current-carrying wires is given by
where
is the vacuum permeability
are the currents in the two wires
r is the separation between the two wires
For the wires in this problem, we have
r = 2.00 cm = 0.02 m
Substituting into the equation, we find
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