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ycow [4]
4 years ago
10

How to find initial velocity in projectile motion problems when you are not given the vlocity?

Physics
1 answer:
Papessa [141]4 years ago
7 0
Vi= square root vi^2 -2ad
You might be interested in
Which process is represented by the PV diagram shown below?
MrMuchimi

Answer: B. the isovolumetric process

Explanation:

In the graph given, the volume is constant throughout. It represents a constant volume process. Such processes are called the isovolumetric process or isochoric process.

<em>Hence, option B is the correct answer.</em>

Option A is incorrect because in an isobaric process, the pressure is constant.

Option C is incorrect because in an isothermal process, the temperature is constant.

Option D is incorrect because in an adiabatic process there is no heat transfer.

8 0
3 years ago
A rocket initially at rest accelerates at a rate of 99. 0 meters/second2. Calculate the distance covered by the rocket if it att
creativ13 [48]

The rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s. Acceleration can be defined as the change in velocity.

<h3>What is acceleration?</h3>

Acceleration can be defined as the change in speed or the direction of the object.

From kinamatic equation:

D = v_{t} +\dfrac 12at^2

Where,

D - final velocity =  445 m/s

v_0 -  initial valocity = 0 m/s

a - acceleration = 99. 0 m/s²

t - time =  4. 50 s

Put the values in the formula,

D = 0\times  ( 4.5) + \dfrac12\times (99)(4.5)^2\\\\D = 1002 {\rm \ m}\\\\D = 1 \times  10^3\rm \ m

Therefore, the rocket will cover 1 \times  10^3\rm \ m distance in 4. 5 s.

Learn more about Acceleration :

brainly.com/question/2697545

7 0
3 years ago
Hiii please help i’ll give brainliest if you give a correct answer please thanks!
mrs_skeptik [129]

Answer:

25 to the right

Explanation:

there you go friend your awsome

4 0
3 years ago
Help pleasessssssssssssss
irinina [24]

Sorry I had the answer but it wont let me type numbers :(.:

5 0
2 years ago
An electron in the n = 5 level of an h atom emits a photon of wavelength 1282.17 nm. to what energy level does the electron move
lions [1.4K]
This is an interesting (read tricky!) variation of Rydberg Eqn calculation.
Rydberg Eqn: 1/λ = R [1/n1^2 - 1/n2^2]
Where λ is the wavelength of the light; 1282.17 nm = 1282.17×10^-9 m
R is the Rydberg constant: R = 1.09737×10^7 m-1
n2 = 5 (emission)
Hence 1/(1282.17 ×10^-9) = 1.09737× 10^7 [1/n1^2 – 1/25^2]
Some rearranging and collecting up terms:
1 = (1282.17 ×10^-9) (1.09737× 10^7)[1/n2 -1/25]
1= 14.07[1/n^2 – 1/25]
1 =14.07/n^2 – (14.07/25)
14.07n^2 = 1 + 0.5628
n = √(14.07/1.5628) = 3
8 0
3 years ago
Read 2 more answers
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