Do as physics instructor fred cauthen does and place a tennis ball close to and above the top of a basketball. drop the balls to
1 answer:
Answer:
after shock
creating a system for the conservation of the energy of the basketball ball and creating a system for the tennis ball only, the conservation of energy should be applied to each system independently
Explanation:
When the two balls fall they acquire the same speed since they are accelerated by the same force, their weight and the acceleration of the acceleration of gravity. When reaching the floor the mechanical energy of the system is conserved.
Upon reaching the floor, the first ball (basketball) collides with the floor, this process is very fast, at the end of the process the basketball comes out with a velicad up and collides with the much lighter tennis ball that is still descending .
we assume that the shocks are elastic, when solving the momentary and kinetic energy findings, we find the velocities after each shock
In this clash the tennis ball acquires a high kinetic speed with an upward direction that makes a very high height high. Again this shock is very fast and the tennis ball almost does not move.
Here we must separate the system, creating a system for the conservation of the energy of the basketball ball and another system for the tennis ball only, the conservation of energy should be applied to each system independently
Em₀ =K = 1/2 m v²
= U = m g h
As in the elastic shock the final speed of the tennis ball is approximately 2 vo, we can calculate the maximum height
m g h = 1/2 m (2v₀)²
h = 2 v₀²/g
To reconcile this with the conservation of energy we must calculate the energy for the tennis ball at two points, the first when the crash with the tennis ball ends and at the end point at its maximum height.
You might be interested in
Answer:
La persona está nadando en la alberca a una profundida de 5.575 metros.
Explanation:
La presión absoluta () experimentada por la persona es la suma de la presión atmosférica (
) y la presión hidrostática de la columna de agua de la alberca (
), medidas en kilopascales. Es decir,
(1)
(2)
Donde:
- Densidad del fluido de la alberca, medida en kilogramos por metro cúbico.
- Aceleración gravitacional, medida en metros por segundo al cuadrado.
- Profundidad de la persona en la alberca, medida en metros.
Si sabemos que ,
,
y
, entonces la profundidad de la persona en la alberca es:
La persona está nadando en la alberca a una profundida de 5.575 metros.
Answer:
Velocity
v= i + 2 j
Acceleration
a= 2 j
Explanation:
Given that
r(t) = t i + t² j + 3 k
We know that
Velocity v given as
v= dr/dt
dr/dt= i + 2 t j +0
v= i + 2 t j
At t= 1
v= i + 2 x 1 j
v= i + 2 j
Acceleration ,a
a= dv/dt
v= i + 2 t j
dv/dt= 2 j
a= 2 j
