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vagabundo [1.1K]
2 years ago
9

Coefficients in a chemical equation express _____ between molecules or compounds.

Chemistry
2 answers:
kotykmax [81]2 years ago
4 0

Coefficients in a chemical equation express RATIOS between molecules or compounds.

In chemistry, coefficients are numerical numbers in front of element or formula. In a chemical equation, coefficients show the number of elements that should react with the number of other elements to produce a particular amount of chemical products.

<h2>Further Explanation</h2>

In other words, coefficients show the number of the molecules of the substance (reactant and products) in a chemical reaction.

For proper clarification: let look at this equation

2 H2 + O2 — 2 H2O

This goes to shows the coefficient in front of each element, which means that the coefficient of H2 is 2, the coefficients 02 is 1 and the coefficient of H20 is 2.

What the equation is showing us is that 2 molecules of hydrogen with one molecule of oxygen will produce 2 molecules of water (H20).

If coefficients are not present in a chemical equation, what it means is that we will only know that a certain reactants will produce a particular products.

However, without the coefficients, we won’t be able to know the ratio at which the elements will react with one another.

Therefore, Coefficients in a chemical equation express RATIOS between molecules or compounds.

LEARN MORE:

  • Coefficients brainly.com/question/12706762
  • Coefficients brainly.com/question/2735017

KEYWORDS:

  • coefficients
  • products
  • reactants
  • compounds
  • molecules
Pavel [41]2 years ago
3 0

Coefficients in a chemical equation express RATIOS between molecules or compounds.

In chemical equations, coefficient refers to those numerical numbers that are usually written at the front of elements' chemical symbols in order to balance the equations. Coefficients tell us the number of a particular element that must react with a specific number of another element in order for certain amount of chemical products to be produced; that is, it provide information about the reaction ratio of reactants and products. For instance, look at this chemical equation: N2 + 3H2 = 2NH3

In the equation given above, the coefficient of N2 is 1, the coefficient of H2 is 3 and the coefficient of NH3 is 2. What this equation is essentially telling us is that, in order to produce two molecules of ammonia, one molecule of nitrogen must react with three molecules of hydrogen. Thus, the equation gives the ratios between the product and the reactants.

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If volumes are additive and 253 mL of 0.19 M potassium bromide is mixed with 441 mL of a potassium dichromate solution to give a
Alexxx [7]

Answer:

The concentration of the Potassium Dichromate solution is 0.611 M

Explanation:

First of all, we need to understand that in the final solution we'll have potassium ions coming from KBr and also K2Cr2O7, so we state the dissociation equations of both compounds:

KBr (aq) → K+ (aq) + Br- (aq)

K2Cr2O7 (aq) → 2K+ (aq) + Cr2O7 2- (aq)

According to these balanced equations when 1 mole of KBr dissociates, it generates 1 mole of potassium ions. Following the same thought, when 1 mole of K2Cr2O7 dissociates, we obtain 2 moles of potassium ions instead.

Having said that, we calculate the moles of potassium ions coming from the KBr solution:

0.19 M KBr: this means that we have 0.19 moles of KBr in 1000 mL solution. So:

1000 mL solution ----- 0.19 moles of KBr

253 mL solution ----- x = 0.04807 moles of KBr

As we said before, 1 mole of KBr will contribute with 1 mole of K+, so at the moment we have 0.04807 moles of K+.

Now, we are told that the final concentration of K+ is 0.846 M. This means we have 0.846 moles of K+ in 1000 mL solution. Considering that volumes are additive, we calculate the amount of K+ moles we have in the final volume solution (441 mL + 253 mL = 694 mL):

1000 mL solution ----- 0.846 moles K+

694 mL solution ----- x = 0.587124 moles K+

This is the final quantity of potassium ion moles we have present once we mixed the KBr and K2Cr2O7 solutions. Because we already know the amount of K+ moles that were added with the KBr solution (0.04807 moles), we can calculate the contribution corresponding to K2Cr2O7:

0.587124 final K+ moles - 0.04807 K+ moles from KBr = 0.539054 K+ moles from K2Cr2O7

If we go back and take a look a the chemical reactions, we can see that 1 mole of K2Cr2O7 dissociates into 2 moles of K+ ions, so:

2 K+ moles ----- 1 K2Cr2O7 mole

0.539054 K+ moles ---- x = 0.269527 K2Cr2O7 moles

Now this quantity of potassium dichromate moles came from the respective  solution, that is 441 mL, so we calculate the amount of them that would be present in 1000 mL to determine de molar concentration:

441 mL ----- 0.269527 K2Cr2O7 moles

1000 mL ----- x = 0.6112 K2Cr2O7 moles = 0.6112 M

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