Answer:
6 Percent Composition. 1. Molar Mass of KBr K = 1(39.10) = 39.10 Br =1(79.90) =79.90 MM = 119.0 79.90 g 119.0 g = 0.6714 3. 0.6714 x 50.0g = 33.6 g Br 2.
The enthalpy of combustion of 1 mole of benzene is 3169 kJ/mol .
The first step in answering this question is to obtain the balanced thermochemical equation of the reaction. The thermochemical equation shows the amount of heat lost or gained.
The thermochemical equation for the combustion of benzene is;
2 C6H6(l) + 15 O2(g) → 12 CO2(g) + 6 H2O(g) ΔrH° = -3169 kJ/mol
We can see that 1 mole of benzene releases about 3169 kJ/mol of heat.
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<u>Answer:</u> The correct answer is saturated solution.
<u>Explanation:</u>
For the given options:
Dilute solutions are defined as the solutions in which solute particles are present in less very amount than the solvent particles.
Unsaturated solutions are defined as the solutions where more and more of solute particles can be dissolved in the given amount of solvent.
Saturated solutions are defined as the solutions where no more solute particles can be dissolved in the solvent. The concentration of the solute particles that can be dissolved in a solution is maximum.
Supersaturated solutions are defined as the solutions where more amount of solute particles are present than the solvent particles.
From the above information, we conclude that the given solution is saturated solution.
Answer: Because Alkalis are bases that can dissolve in water, which can also neutralize acid.
The upper chambers are called the left and right atria, and the lower chambers are called the left and right ventricles. A wall of muscle called the septum separates the left and right atria and the left and right ventricles
