1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka2103 [35]
3 years ago
11

The graph shows the solubility of several different salts in water, across a range of temperatures. According to the

Chemistry
2 answers:
DiKsa [7]3 years ago
5 0

Answer:

D. Potassium Nitrate

Explanation:

If you're using usa test prep.

sladkih [1.3K]3 years ago
4 0

Answer:

  • <u><em>Sodium chloride</em></u>
  • See the graph attached

Explanation:

The attached graph with a green and a red arrow facilitates the understanding of this explanation.

To read the <em>solubility </em>on the <em>graph</em>, you can start with the temperature, on the x-axis.

The red vertical arrow shows how, departing from the <em>40ºC temperature</em> on the x-axis, you intersect the<em> solutibility curve </em>of sodium chloride at a height (y-axis) corresponding to <em>60 g/100cm³ of water</em> (follow the green horizontal arrow).

Hence, <em>sodium chloride is the salt that can dissolve at a concentration of about 60g/100cm³ of water at 40ºC.</em>

You might be interested in
Which of the following is NOT true about energy?*
Montano1993 [528]

Answer:

the last one

Explanation:

although energy can be transferred it does not change after a transfer

7 0
3 years ago
There is an error in the rate-determining step of the following proposed mechanism.
yulyashka [42]

Answer:

The steps with correct mechanism are given below:

C

1) CH₄(g) + Cl(g) → CH₃(g) + HCl(g) : This is a slow step.

The rate is given as: R1 = k₁[CH₄][Cl]  

2) CH₃(g) + Cl₂(g) → CH₃Cl(g) + Cl(g): This is a fast step.

The rate is given as: Rate = k₂[CH₃][Cl₂]  

∴ CH₄(g) + Cl₂(g) → CH₃Cl(g) + HCl(g)

Here, the slowest step will be the rate-determining step.

5 0
3 years ago
10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what
igor_vitrenko [27]

Answer:

569K

Explanation:

Q = 3.5kJ = 3500J

mass = 28.2g

∅1 = 20°C = 20 + 273 = 293K

∅2 = x

c = 0.449

Q = mc∆∅

3500 = 28.2×0.449×∆∅

3500 = 12.6618×∆∅

∆∅ = 3500/12.6618

∆∅ = 276.4220

∅2 - ∅1 = 276.4220

∅2 = 276.4220 + ∅1

∅2 = 276.4220 + 293

∅2 = 569.4220K

∅2 = 569K

3 0
3 years ago
What’s the empirical formula of taurine
zhenek [66]

Answer: The formula is <u>C2H7NO3S</u> or <u>NH2CH2CH2SO3H</u>

<u />

Hope this helps!

3 0
2 years ago
Technetium-99 is an ideal radioisotope for scanning organs because it has a half-life of 6.0 h and is a pure gamma emitter. supp
Nadusha1986 [10]

Answer: 20 mg Te-99 remains after 12 hours.

Explanation:  N(t) = N(0)*(1/2)^(t/t1/2)

                        N(t) = (80 mg)*(0.5)^(12/6)

N(t) = 20 mg remains after 12 hours

3 0
3 years ago
Other questions:
  • The increase in the population of people living in urban areas will cause a decrease in urban sprawl.
    15·2 answers
  • According to john dalton, elements consist of tiny particles called __________. Atoms of each element are __________ to each oth
    6·1 answer
  • How many moles of h2so4 is produced from 12.5 moles of so2?
    6·1 answer
  • A substance is analyzed and found to consist of 0.360 g of Na, 0.220 g of N, and 0.752 g of O. How many moles of Na, N, and O ar
    13·2 answers
  • The steps to balancing a neutralization reaction when given a verbal description can be summarized as follows: Write the chemica
    8·1 answer
  • Give one difference between molecule of an element and molecule of a compound with examples​
    9·1 answer
  • Which of the following is an example of a conjugate acid-base pair?​
    9·2 answers
  • If the molar heat of vaporization for water is 40.7 kJ/mol. What is the molar heat of condensation? HELP ME PLEASE!!!
    14·1 answer
  • Help me please ........
    9·1 answer
  • Which of these is an example of chemical change
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!