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const2013 [10]
3 years ago
7

Violet light has a frequency of 7.26 * 1014 Hz and travels at a speed of 3.00 * 108 m/s.

Chemistry
2 answers:
Mars2501 [29]3 years ago
6 0

Answer : The wavelength of violet light is, 413 nm

Explanation :

Formula used :

\nu=\frac{c}{\lambda}

where,

\nu = frequency of violet light = 7.26\times 10^{14}Hz=7.26\times 10^{14}s^{-1}

As we know that, Hz=s^{-1}

\lambda = wavelength of violet light

c = speed of light = 3.00\times 10^8m/s

Now put all the given values in the above formula, we get:

7.26\times 10^{14}s^{-1}=\frac{3.00\times 10^8m/s}{\lambda}

\lambda=\frac{3.00\times 10^8m/s}{7.26\times 10^{14}s^{-1}}

\lambda=4.13\times 10^{-7}m=4.13\times 10^{-7}\times 10^9nm=413nm

conversion used : 1m=10^9nm

Therefore, the wavelength of violet light is, 413 nm

Romashka [77]3 years ago
5 0

c=λν

3*10^8 m/s * 10^9 nm/m / 7.26*10^14 s^-1= λ

=413.22 nm

λ=413 nm

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g 304 mL of a 0.36 M potassium hydroxide solution is added to 341 mL of a 0.51 M lithium hydroxide solution. Calculate the pOH o
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<u><em></em></u>

  • <u><em>pOH = 0.36</em></u>

Explanation:

Both <em>potassium hydroxide</em> and <em>lithium hydroxide </em>solutions are strong bases, so you assume 100% dissociation.

<u>1. Potassium hydroxide solution, KOH</u>

  • Volume, V = 304 mL = 0.304 liter
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  • number of moles, n = M × V = 0.36M × 0.304 liter = 0.10944 mol
  • 1 mole of KOH produces 1 mol of OH⁻ ion, thus the number of moles of OH⁻ is 0.10944

<u>2. LIthium hydroxide, LiOH</u>

  • Volume, V = 341 mL = 0.341 liter
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  • number of moles, n = M × V = 0.341 liter × 0.51 M = 0.17391 mol
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<u />

<u>3. Resulting solution</u>

  • Number of moles of OH⁻ ions = 0.10944 mol + 0.17391 mol = 0.28335 mol

  • Volume of solution = 0.304 liter + 0.341 liter = 0.645 liter

  • Molar concentration = 0.28335 mol / 0.645 liter = 0.4393 M

<u />

<u>4. </u><em><u>pOH</u></em>

      pOH=-\log [OH^-]=-\log (0.439)=0.36   ← answer

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3 years ago
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