Strength of the magnetic field: 20 T
Explanation:
For a conductive wire moving perpendicular to a magnetic field, the electromotive force (voltage) induced in the wire due to electromagnetic induction is given by
where
B is the strength of the magnetic field
v is the speed of the wire
L is the length of the wire
For the wire in this problem, we have:
(induced emf)
L = 0.20 m (length of the wire)
v = 3.0 m/s (speed)
Solving for B, we find the strength of the magnetic field:
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Answer:
8. acceleration = = 1 unit .
9. acceleration = = -1 unit.
10. acceleration = = 0 units.
Explanation:
8. i) acceleration = velocity / time
ii) In this figure velocity = time
iii) therefore acceleration = = 1 unit .
9. i) acceleration = velocity / time
ii) In this figure 4 = m + 5, therefore m = -1
therefore velocity = (-0.5 time) + 5
iii) therefore acceleration = = -1 units.
10.) velocity is constant at 2
therefore acceleration = = 0 units
Answer:
v₁ = -0.8087 m / s
Explanation:
To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved
Initial instant. When they are united
p₀ = 0
Final moment. After throwing the brick
= (m_man + m_skate) v1 + m_brick v2
the moment is preserved
p₀ = p_{f}
0 = (m_man + m_skate) v₁ + m_brick v₂
v₁ = -
the negative sign indicates that the two speeds are in the opposite direction
let's calculate
v₁ = -
v₁ = -0.8087 m / s
Answer:
Explanation:
Given
--- Surface Tension
--- Radius
Required
Determine the required force
First, we calculate the circumference (C) of the circular plate
The applied force is then calculated using;