The constant force applied to the rope is 7.72 N.
<h3>Net torque on the drum</h3>
The net torque on the drum is calculated as follows;
Linear speed, v = ωr = 23 x 0.4 = 9.2 m/s
distance traveled = 14 m
<h3>Tangential acceleration</h3>
The acceleration of the drum is calculated as follows;
v² = u² + 2as
v² = 0 + 2as
v² = 2as
a = v²/2s
a = (9.2)/2(14)
a = 0.329 m/s²
<h3>Angular acceleration of the drum</h3>
<h3>Applied force</h3>
The constant force applied to the rope is calculated as follows;
Learn more about net torque here: brainly.com/question/15262027
Answer:
Explanation:
Let E be the strength of electric field and m be the mass of plastic sphere.
charge on plastic sphere, q = - 3 n C = - 3 x 10^-9 C
The force due to electric field on the charged plastic sphere = q E
The weight of the plastic sphere = m g
where, g is the acceleration due to gravity.
Now the force due to electrostatic field is balanced by teh weight of the plastic sphere.
q E = m g
E = m g / q
E = m x 9.8 / (3 x 10^-9) = 3.26 x 10^9 x m
Substitute the value of m and get the value E.
Answer: a. F doubled
b. F reduced by one-quarter i.e
1/4*(F)
c. 1/9*(F)
d. F increased by a factor of 4 i.e 4*F
e. F reduces 3/4*(F)
Explanation: Coulombs law states the force F of attraction/repulsion experience by two charges qA and qB is directly proportional to thier product and inversely proportional to the square of distance d between them. That is
F = k*(qA*qB)/d²
a. If qA is doubled therefore the force is doubled since they are directly proportional.
b. If qA and qB are half, that means thier new product would be qA/2)*qB/2 =qA*qB/4
Which means the product of charge is divided by 4 so the force would be divided by 4 too since they are directly proportional.
c. If d is tripped that is multiplied by 3. From the formula new d would be (3*d)²=9d² but force is inversely proportional to d² so instead of multiplying by 9 the force will be divided by 9
d. If d is cut into half that is divided by 2. The new d would be (d/2)²=d²/4. So d² is divided by 4 so the force would be multiplied by 4
e. If qA is tripled that is multiplied by 3. F would be multiplied by 3 also, if at the same time d is doubled (2*d)²= 4*d² . Force would be divided by 4 at same time. So we have,
3/4*F
Average speed = (total distance covered) / (time to cover the distance)
= (50 miles) / (1.5 hours)
= (50/1.5) miles/hours
= (33 and 1/3) mph .
We don't care about all that other "data" given earlier in the question.
We only need to know the total distance covered and the time it took
to cover the distance.
Answer:
Explanation:
The amount of heat released from water is equal to the sum of latent and sensible heats. Let suppose that water is initially at a temperature of 
. Then:
Finally, the amount of heat released from water is now computed by replacing variables:
![\Delta H_{tot} = (1\,mol)\cdot \left[\left(75.3\,\frac{kJ}{mol\cdot K} \right)\cdot (25^{\circ}C-0^{\circ}C)+ 6.025\,\frac{kJ}{mol} + \left(37.7\,\frac{kJ}{mol\cdot K} \right)\cdot (0 + 10^{\circ}C)\right]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Btot%7D%20%3D%20%281%5C%2Cmol%29%5Ccdot%20%5Cleft%5B%5Cleft%2875.3%5C%2C%5Cfrac%7BkJ%7D%7Bmol%5Ccdot%20K%7D%20%5Cright%29%5Ccdot%20%2825%5E%7B%5Ccirc%7DC-0%5E%7B%5Ccirc%7DC%29%2B%206.025%5C%2C%5Cfrac%7BkJ%7D%7Bmol%7D%20%2B%20%5Cleft%2837.7%5C%2C%5Cfrac%7BkJ%7D%7Bmol%5Ccdot%20K%7D%20%5Cright%29%5Ccdot%20%280%20%2B%2010%5E%7B%5Ccirc%7DC%29%5Cright%5D)
