Answer:
The answer is given below in the picture
Explanation:please check it
Answer:
Explanation:
The definition of acids and bases by Arrhenius Theory was modified and extended by Bronsted-Lowry.
Bronsted-Lowry defined acid as a molecule or ion which donates a proton while a base is a molecule or ions that accepts the proton. This definition can be extended to include acid -base titrations in non-aqueous solutions.
In this theory, the reaction of an acid with a base constitutes a transfer of a proton from the acid to the base.
From the given information:
![\mathsf{HCN _{(aq)} + H_2O_{(l)} \to CN^{-}_{(aq)} + H_3O_{(aq)}}](https://tex.z-dn.net/?f=%5Cmathsf%7BHCN%20_%7B%28aq%29%7D%20%2B%20H_2O_%7B%28l%29%7D%20%5Cto%20CN%5E%7B-%7D_%7B%28aq%29%7D%20%2B%20H_3O_%7B%28aq%29%7D%7D)
From above:
We will see that HCN releases an H⁺ ion, thus it is a Bronsted-Lowry acid
accepts the H⁺ ion ,thus it is a Bronsted-Lowry base.
The formula of the reactant that acts as a proton donor is <u>HCN</u>
The formula of the reactant that acts as a proton acceptor is <u>H2O</u>
Answer: 58.44g
Explanation: The molar mass of NaCl is 58.44g.
Answer:
![M_f=38.8\%](https://tex.z-dn.net/?f=M_f%3D38.8%5C%25)
Explanation:
From the question we are told that:
Pressure ![P=747mmHg](https://tex.z-dn.net/?f=P%3D747mmHg)
Temperature ![T=298K](https://tex.z-dn.net/?f=T%3D298K)
Volume ![V=11.1](https://tex.z-dn.net/?f=V%3D11.1)
Heat Produced ![Q=780kJ](https://tex.z-dn.net/?f=Q%3D780kJ)
Generally the equation for ideal gas is mathematically given by
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
![n= (747/760) *11.1/ (0.0821*298)](https://tex.z-dn.net/?f=n%3D%20%28747%2F760%29%20%2A11.1%2F%20%280.0821%2A298%29)
![n=0.446mol](https://tex.z-dn.net/?f=n%3D0.446mol)
Therefore
![x+y=0.446](https://tex.z-dn.net/?f=x%2By%3D0.446)
![x=0.446-y .....1](https://tex.z-dn.net/?f=x%3D0.446-y%20.....1)
Since
Heat of combustion of Methane=889 kJ/mol
Heat of combustion of Propane=2220 kJ/mol
Therefore
![x(889) + y(2220) = 760 ...... 2](https://tex.z-dn.net/?f=x%28889%29%20%2B%20y%282220%29%20%3D%20760%20......%202)
Comparing Equation 1 and 2 and solving simultaneously
![x=0.446-y .....1](https://tex.z-dn.net/?f=x%3D0.446-y%20.....1)
![x(889) + y(2220) = 760 ...... 2](https://tex.z-dn.net/?f=x%28889%29%20%2B%20y%282220%29%20%3D%20760%20......%202)
![x=0.173](https://tex.z-dn.net/?f=x%3D0.173)
![y=0.273](https://tex.z-dn.net/?f=y%3D0.273)
Therefore
Mole fraction 0f Methane is mathematically given as
![M_f=\frac{x}{n}*100\%](https://tex.z-dn.net/?f=M_f%3D%5Cfrac%7Bx%7D%7Bn%7D%2A100%5C%25)
![M_f=\frac{1.173}{0.446}*100\%](https://tex.z-dn.net/?f=M_f%3D%5Cfrac%7B1.173%7D%7B0.446%7D%2A100%5C%25)
![M_f=38.8\%](https://tex.z-dn.net/?f=M_f%3D38.8%5C%25)