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Inessa [10]
3 years ago
10

A reaction was set up to convert an alcohol to a carbonyl Samples of the reaction mixture were checked by infrared spectrometry

every couple of minutes. Use the infrared spectra provided to determine if the reaction mixture contains: pure alcohol, a mixture of alcohol and carbonyl, or pure carbonyl pure alcohol O pure carbonyl O mixture of alcohol and carbonyl 1000 500 O O O pure alcohol pure carbonyl mixture of alcohol and carbonyl 70

Chemistry
1 answer:
QveST [7]3 years ago
6 0

Answer:

look at peaks:

sharp peak at ~ 1700 = carbonyl

broad peak at ~ 3300 = alcohol

both = mixture

Explanation:

In the first spectrum, the broad peak occurring in the range of 3300-3700 cm-1 corresponds to OH bond stretch frequency. Carbonyl C=O bond stretch has a frequency range of 1670-1820 cm-1. The absence of any peaks in this region in the given spectrum rules out the presence of carbonyl compound in the reaction mixture. So, the reaction mixture contains only pure alcohol.

The second spectrum shows a peak around 1700 cm-1 corresponding to the carbonyl compound along with the broad peak around 3300 cm-1 corresponding to alcohol. So, the reaction mixture contains both alcohol and carbonyl compounds.

A table containing different functional groups and their corresponding Infra Red frequencies is given below for further references

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Leona [35]

To prepare 350 mL of 0.100 M solution from a 1.50 M solution, we simply have to use the formula:

M1 V1 = M2 V2

So from the formula, we will know how much volume of the 1.50 M we actually need.

 

1.50 M * V1 = 0.100 M * 350 mL

V1 = 23.33 mL

 

So we need 23.33 mL of the 1.50 M solution. We dilute it with water to a volume of 350 mL. So water needed is:

350 mL – 23.33 mL = 326.67 mL water

 

 

Steps:

1. Take 23.33 mL of 1.50 M solution

<span>2. Add 326.67 mL of water to make 350 mL of 0.100 M solution</span>

7 0
3 years ago
Emma strikes a match and sets some logs on fire. As the fire burns, which two forms of energy are released?
Ivanshal [37]

Answer:

Explanation:

There are changes in the chemical composition of the word.

There's light energy given off.

There's heat energy given up.

7 0
3 years ago
How many atoms are here in the following?
Elina [12.6K]

Answer:

A. 6N

B. 4H, 2O

C. 4H, 4N, 12O

D. 2Ca, 4O, 4H

E. 3Ba, 6Cl, 18O

F. 5Fe, 10N, 30O

G. 12Mg, 8P, 32O

H. 4N, 16H, 2S, 8O

I. 12Al, 18Se, 72O

J. 12C, 32H

I am 90% sure this is correct

6 0
3 years ago
The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat
Darya [45]

Answer:

Heat of fusion

Explanation:

The heat required to change 1 gram of a solid at its normal melting point to a liquid at the same temperature is called the heat of fusion.

The formula for the heat of fusion is given by :

\Delta H=n\Delta H_{fus}

Where

n is no of moles

\Delta H_{fus} is molar heat of the substance

Hence, the correct answer is heat of fusion

8 0
3 years ago
Help! I need help on how to do these problems.
svetlana [45]

Answer:

a. 3; b. 5; c. 10; d. 12

Explanation:

pH is defined as the negative log of the hydronium concentration:

pH = -log[H₃O⁺] (hydronium concentration)

For problems a. and b., HCl and HNO₃ are strong acids. This means that all of the HCl and HNO₃ would ionize, producing hydronium (H₃O⁺) and the conjugate bases Cl⁻ and NO₃⁻ respectively. Further, since all of the strong acid ionizes, 1 x 10⁻³ M H₃O⁺ would be produced for a., and 1.0 x 10⁻⁵ M H₃O⁺ for b. Plugging in your calculator -log[1 x 10⁻³] and -log[1.0 x 10⁻⁵] would equal 3 and 5, respectively.

For problems c. and d. we are given a strong base rather than acid. In this case, we can calculate the pOH:

pOH = -log[OH⁻] (hydroxide concentration)

Strong bases similarly ionize to completion, producing [OH⁻] in the process; 1 x 10⁻⁴ M OH⁻ will be produced for c., and 1.0 x 10⁻² M OH⁻ produced for d. Taking the negative log of the hydroxide concentrations would yield a pOH of 4 for c. and a pOH of 2 for d.

Finally, to find the pH of c. and d., we can take the pOH and subtract it from 14, giving us 10 for c. and 12 for d.

(Subtracting from 14 is assuming we are at 25°C; 14, the sum of pH and pOH, changes at different temperatures.)

6 0
3 years ago
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