Length = 3.1748 meters
Width = 3.1748 meters
Height = 3.1748 meters
Surface area = 5 · 3.1748²
Surface area = 50.397 meters²
Answer:
The ratio of the young's modulus of steel and copper is
(c) is correct option.
Explanation:
Given that,
Length of steel wire = 4.7 m
Cross section
Length of copper wire = 3.5 m
Cross section
We need to calculate the ratio of young's modulus of steel and copper
Using formula of young's modulus for steel wire
....(I)
The young's modulus for copper wire
....(II)
From equation (I) and (II)
The ratio of the young's modulus of steel and copper
Hence, The ratio of the young's modulus of steel and copper is
Answer:
(A) Total energy will be equal to
(b) Energy density will be equal to
Explanation:
We have given diameter of the plate d = 2 cm = 0.02 m
So area of the plate
Distance between the plates d = 0.50 mm =
Permitivity of free space
Potential difference V =200 volt
Capacitance between the plate is equal to
(a) Total energy stored in the capacitor is equal to
(b) Volume will be equal to , here A is area and d is distance between plates
So energy density