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Studentka2010 [4]
3 years ago
5

Na sua época quais foram as condições experimentais que Lavoisier utilizou em suas experiências ?

Chemistry
1 answer:
Olin [163]3 years ago
3 0

Answer:

What are u saying

Explanation:

umm ok sorry i didnt understand anything

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Fix the formula for KF2<br> Write out the full correct formula?
Korvikt [17]

Given :

A chemical compound KF_2 .

To Find :

Fix the formula for KF_2 and write the full correct formula.

Solution :

We know, Potassium( K ) and Fluorine( F ) both have a valency of 1 i.e potassium can donate one electron and Fluorine can accept one electron only.

So, the chemical formula KF_2 is wrong because no element has filled electron.

Therefore, to stabilise the molecule, 1 Potassium atom should make a bond from 1 Fluorine i.e KF ( correct formula ) .

Hence, this is the required solution.

7 0
3 years ago
A workman uses a moveable pulley to lift a heavy load of bricks. What is the input force, if the output force is 150 N?
NeTakaya

Answer:

the input force would be 75 N

Explanation:

if the output force is 150 N you divide that in half which leaves with 75 N !! :)

7 0
3 years ago
What controls flowering in many<br> plants?
katrin2010 [14]

Answer:

All flowering is regulated by the integration of environmental cues into an internal sequence of processes. These processes regulate the ability of plant organs to produce and respond to an array of signals. The numerous regulatory switches permit precise control over the time of flowering.

Explanation:

3 0
3 years ago
A sample of oxalic acid (a diprotic acid of the formula H2C2O4) is dissolved in enough water to make 1.00 L of solution. A 100.0
OleMash [197]

<u>Answer:</u> The mass of original oxalic acid sample is 6.75 grams

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2C_2O_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=?M\\V_1=100.0mL\\n_2=1\\M_2=0.750M\\V_2=20.0mL

Putting values in above equation, we get:

2\times M_1\times 100.0=1\times 0.750\times 20.0\\\\M_1=\frac{1\times 0.750\times 20.0}{2\times 100.0}=0.075M

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}

Given mass of oxalic acid = ? g

Molar mass of oxalic acid = 90 g/mol

Molarity of solution = 0.075 M

Volume of solution = 1.00 L

Putting values in above equation, we get:

0.075M=\frac{\text{Mass of oxalic acid}}{90g/mol\times 1L}\\\\\text{Mass of oxalic acid}=(0.075\times 90\times 1)=6.75g

Hence, the mass of original oxalic acid sample is 6.75 grams

7 0
3 years ago
1. Matter can be measured in many ways for specific purposes. Which measurement depends on the force of gravity it is not reliab
Ganezh [65]

Answer:

1. B- weight

2. B- 2.0g/cm3

3. C- 22.8g/cm3

Explanation:

6 0
3 years ago
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