Nor liquid or solid since flubber is like oobleck, it is a non newtonian object.
Answer:
-4.1°C
Explanation:
The freezing-point depression (ΔTf) is a colligative property that can be calculated using the following expression:
ΔTf = i × Kf × m
where,
i: van't Hoff factor
Kf: freezing-point depression constant
m: molality
ΔTf = 1.9 × 1.86°C/m × 1.15 m = 4.1 °C
The freezing-point of pure water is 0°C. The freezing-point of this solution is:
0°C - 4.1°C = -4.1°C
Assuming we have 100 g of sample
30.45/MW of N 14g = 2.175
69.55/MW of O 16g = 4.34
4.34/2.185 = 2
for every 1 mole of N we have 2 moles of O
so the empirical formula would be NO2
without having the molecular weight of the entire molecule the molecular formula can not be determined with the information in your question
I'm not sure what the question is but 3 is an example of a prime number. I hope this help
Answer:
*result with sodium hydroxide: white ppt of Zn(OH)2
*excess sodium hydroxide: Precipitate dissolves to form a COLOURLESS solution
*Result with Aqueous ammonia: White ppt of Zn(OH)2
*excess aqueous ammonia: Precipitate dissolves to form a COLOURLESS solution
