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Juli2301 [7.4K]
3 years ago
13

Having the correct posture and the degree or severity of braking, acceleration and steering inputs have a direct result on the a

bility of a motorist to effectively address changes in __________?
Physics
1 answer:
kaheart [24]3 years ago
8 0

Answer: Vehicle Balance

Explanation:

Vehicle balance simply means how the weight of a vehicle is distributed across its tires which connects to the road

It should be noted that there'll be a shift in the balance of a vehicle when the braking, acceleration, or turning bring about a scenario in which the weight of th vehicle moves from one area to another.

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Write examples of adaptation in mangrove .? <br>what are the adaptation of rainforest.?​
Sergio039 [100]

Answer:

example of adaptation in mangrove

Mangroves are salt-tolerant trees, also called halophytes, and are adapted to life in harsh coastal conditions. They contain a complex salt filtration system and complex root system to cope with salt water immersion and wave action. They are adapted to the low oxygen conditions of waterlogged mud.

adaptation of rainforest

Many animals have adapted to the unique conditions of the tropical rainforests.

hope this can help you

6 0
3 years ago
Brass is an alloy made from copper and zinc a 0.59 kg brass sample at 98.0 is dropped into 2.80 kg of water at 5.0 c if the equi
zhannawk [14.2K]
The specific heat capacity of brass would be ranked between 0 and infinity
3 0
3 years ago
Read 2 more answers
A solid, uniform sphere of mass 2.0 kg and radius 1.7 m rolls without slipping down an inclined plane of height 5.3 m. what is t
inn [45]
<span>Answer: Total kinetic energy at the bottom = 0.5(1+0.4) mv^2 = mgh V^2 = 7*9.8/0.7 V = 9.9m/s ω = V/r = 9.9/1.7 = 5.8rad/s Answer c. 5.8 rad/s</span>
7 0
4 years ago
Air flows through a nozzle at a steady rate. At the inlet the density is 2.21 kg/m3 and the velocity is 20 m/s. At the exit, the
Vitek1552 [10]

To solve the problem, it is necessary to apply the concepts related to the change of mass flow for both entry and exit.

The general formula is defined by

\dot{m}=\rho A V

Where,

\dot{m} = mass flow rate

\rho = Density

V = Velocity

Our values are divided by inlet(1) and outlet(2) by

\rho_1 = 2.21kg/m^3

V_1 = 20m/s

A_1 = 60*10^{-4}m^2

\rho_2 = 0.762kg/m^3

V_2 = 160m/s

PART A) Applying the flow equation we have to

\dot{m} = \rho_1 A_1 V_1

\dot{m} = (2.21)(60*10^{-4})(20)

\dot{m} = 0.2652kg/s

PART B) For the exit area we need to arrange the equation in function of Area, that is

A_2 = \frac{\dot{m}}{\rho_2 V_2}

A_2 = \frac{0.2652}{(0.762)(160)}

A_2 = 2.175*10^{-3}m^2

Therefore the Area at the end is 21.75cm^2

3 0
4 years ago
A planet's distance from the sun is 2.0x10^11 m. what is the orbital period?
Korolek [52]

Answer:

The square of the orbital period of a planet is directly proportional to the cube of the semimajor axis of its orbit.

Explanation:

hope this helps.

4 0
3 years ago
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