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3 years ago

Which safety procedure should you follow after breaking a mercury thermometer?

1 answer:

3 0

B. move away from the mercury and notify the teacher :)

you should never use a broom to sweep mercury, it breaks the mercury in smaller droplets and spread them.
Pouring the mercury in the sink would likely be logged in the plumbing. and pickingthings up with the napkin may cause contamination and cuts from the glass.

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A graduated cylinder is filled with water to the 24-mL mark. When a rock is placed in the cylinder, the level rises to the 53-mL

harkovskaia [24]

30ml is the correct answer to your question hope i can help

6 0

3 years ago

An object that is accelerating may be

Elenna [48]

It must be either speeding up, or slowing down, or turning. There are no other possibilities.

6 0

3 years ago

How many excess electrons must be distributed uniformly within the volume of an isolated plastic sphere 25.0 cm in diameter to p

katrin [286]

Answer:

Required charge $q=2.6\times 10^{9}C$ .

$n=1.622\times 10^{10}\ electrons$

Explanation:

Given:

Diameter of the isolated plastic sphere = 25.0 cm

Magnitude of the Electric field = 1500 N/C

now

Electric field (E) is given as:

$E =\frac{kq}{r^2}$

where,

k = coulomb's constant = 9 × 10⁹ N

q = required charge

r = distance of the point from the charge where electric field is being measured

The value of r at the just outside of the sphere = $\frac{25.0}{2}=12.5cm=0.125m$

thus, according to the given data

$1500N/C=\frac{9\times 10^{9}N\times q}{(0.125m)^2}$

$q=\frac{0.125^2\times 1500}{9\times 10^{9}}$

Required charge $q=2.6\times 10^{9}C$ .

Now,

the number of electrons (n) required will be

$n=\frac{required\ charge}{charge\ of\ electron}$

$n=\frac{2.6\times 10^{-9}}{1.602\times 10^{-19}}$

$n=1.622\times 10^{10}\ electrons$

6 0

4 years ago

A 70.0 kg sprinter starts a race with an acceleration of 2.00 m/s2. If the sprinter accelerates at that rate for 29 m, and then

andrey2020 [161]

Answer:

t = 12.82s

Explanation:

F = m×a

= (70)×(2)

= 140 N

during the acceleration, the sprinter cover d = 29 m with time:

d = 1/2×at

29 = 1/2×(2)×t^2

t^2 = 29s

t = 5.39s

and attains the velocity of:

v = a×t

= 2×5.39

= 10.77 m/s

Then,to cover the last x = 80 m with a speed of 10.77 m/s in time:

t = x/v

= 80/10.77

= 7.43s

Therefore, it will take the sprinter 7.43 + 5.39 = 12.82s

6 0

3 years ago

What are the two ways to keep us fit and healthy ??

AysviL [449]

Answer:

1)Eat healthy food

2)Exercise daily

3)Drink plenty of water

4)Get plenty of sleep

5)Do not take stress

6)Be hygienic

Explanation:

Hope it help Please mark me as brainlest

4 0

3 years ago