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3 years ago

Which safety procedure should you follow after breaking a mercury thermometer?

1 answer:

3 0

B. move away from the mercury and notify the teacher :)

you should never use a broom to sweep mercury, it breaks the mercury in smaller droplets and spread them.
Pouring the mercury in the sink would likely be logged in the plumbing. and pickingthings up with the napkin may cause contamination and cuts from the glass.

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Mass m is fired to the right at a speed of 7.0 m/s where it collides and becomes imbedded in mass M which is hanging from a rope

Tanya [424]

Answer:

V=0.28m/s, the combined mass will be 0.28m/s fast

h=0.00399m

Explanation:

Mass m is fired to the right at a speed of 7.0 m/s where it collides and becomes imbedded in mass M which is hanging from a rope. Mass m is 0.50kg and mass M is 12.0kg. a- How fast will the combined mass (m+M) be moving just after the collision? b- What is the maximum height the system (m+M) will reach?

step by step explanation:

from the principles of linear momentum which states that the total momentum before collision is equal to the total momentum after collision

momentum before collision=momentum after collision

notice that in this this case the collision is inelastic, owing to the fact that the two bodies stuck together after collision

mu+Mu2=(m+M)V

V=common velocity after collision

m=mass of the body fired

M=Mass hanging on the rope

u=velocity of the body

u2=velocity of the mass hanging on arope 0m/s

0.5*7+0=(0.5+12)V

3.5=12.5V

V=3.5/12.5

V=0.28m/s, the combined mass will be 0.28m/s fast

b. the maximum height reached after the impact

starting with the swing of the pendulum just after the collision until it reaches its maximum height. Conservation of mechanical energy applies here, so:

kinetic energy =potential energy

½ (m+M)V = (m+M)gh.

So, the speed of the system immediately after the collision is:

V = (2gh)½

0.28=(2*9.81*h)^0.5

0.0784=2*9.81h

h=0.00399m

8 0

4 years ago

Water freezes at _____. 273°c -273°c 273 k -273 k

AURORKA [14]

273 k hope this helps :)

6 0

4 years ago

Read 2 more answers

There are two particles with charges +Q and +q. The electric force applied to one of the charges is 10 N. Now, +Q is replaced by

KIM [24]

Answer:

F = 10 N

Explanation:

Assuming that we can treat to both particles as point charges, the magnitude of the force that one charge exerts on the other, must obey Coulomb's Law.
The expression for this force, applied to the charges +Q and +q, separated by a distance d, is as follows:

$F_{0} = \frac{k*q*Q}{d^{2}}$

If we replace +Q by +4Q, and d by 2*d, the new expression for the magnitude of the force is as follows:

$F_{1} = \frac{k*q*4*Q}{(2*d)^{2} } = \frac{4}{4} *\frac{k*q*Q}{d^{2} } = F_{0} = 10 N$

As it can be seen, the force will be as same as before making changes, so F= 10 N.

6 0

3 years ago

a body accelerates uniformly from rest at 2m/s^2 for 5 seconds. Calculate its averege velocity in this time

Lana71 [14]

HERE IS YOUR ANSWER!

8 0

3 years ago

A 75-hp (shaft output) motor that has an efficiency of 91.0 percent is worn out and is to be replaced by a high- efficiency moto

daser333 [38]

Convert the shaft ouput from HP to kW

Shaft output = 75HP = 55.93kW

1st: Finding for the power consumption based on 55.93kW output

Power consumption (Old) = 55.93kW / .910 = 61.46kW

Power consumption (New) = 55.93kW / .954 = 58.63kW

2nd: Total power used in kWh:

Power Used = Power consumption * load factor * Hours:

Power (Old) = 61.46kW * .75 * 4368 = 201343 kWh

Power (New) = 58.63kW * .75 * 4368 = 192072 kWh

Energy saved = 201343 kWh - 192072 kWh = 9,271 kWh

3rd: Calculating for the price:

Price = kW-Hr * $/kWh

Price (Old) = 201343kWh * $0.08/kWh = $16107.44

Price (New) = 192072 kWh * $0.08/kWh = $15365.76

Cost saved = $16107.44 - $15365.76 = $741.68/yr

4th: Setting up the cost equation:

Cost over time, F(t) = Motor_Cost + (Price * Number of Years, t)

Cost (Old) = 5449 + 16107.44*t

Cost (New) = 5520 + 15365.76*t

Equate the two to find for t when they cost equally:

5449 + 16107.44*t = 5520 + 15365.76*t

16107.44*t = 15365.76*t +71

16107.44*t - 15365.76*t = 71

741.68*t = 71

t = 71 / 741.68 = .095 years = 35 days

So the payback period is after 35 days.

6 0

3 years ago