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3 years ago

Cole drives to school from home, starting from rest and accelerating for 10 minutes as he travels 6.0 km to school.

Physics

1 answer:

Firlakuza [10]3 years ago

3 0

Explanation:

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P14.003A spherical gas-storage tank with an inside diameter of 8.1 m is being constructed to store gas under an internal pressur

Artist 52 [7]

Answer:

The minimum wall thickness required for the spherical tank is 0.0189 m

Explanation:

Given data:

d = inside diameter = 8.1 m

P = internal pressure = 1.26 MPa

σ = 270 MPa

factor of safety = 2

Question: Determine the minimum wall thickness required for the spherical tank, tmin = ?

The allow factor of safety:

$\sigma _{a} =\frac{\sigma }{factor-of-safety} =\frac{270}{2} =135MPa$

The minimun wall thickness:

$t=\frac{Pd}{4\sigma _{a} } =\frac{1.26*8.1}{4*135} =0.0189m$

3 0

3 years ago

At what speed, as a fraction of c, does a moving clock tick at four fifth the rate of an identical clock at rest?

ololo11 [35]

Answer:

The seed as a fraction of the speed of light is $\frac{3}{5}c$

Solution:

As per the question:

Suppose, $t_{i}$ be the rate of an identical clock between two time intervals.

For a moving clock, moving with velocity 'v', at the clock tick of four-fifth:

t = $\frac{5}{4}t_{i}$

Now,

Using the relation of time dilation, from Einstein's relation:

$t = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

$\frac{5}{4}t_{i} = \frac{t_{i}}{\sqrt{1 - \frac{v^{2}}{c^{2}}}}$

Squaring both sides:

$(\frac{5}{4})^{2} = (\frac{1}{\sqrt{1 - \frac{v^{2}}{c^{2}}}})^{2}$

$\frac{25}{16} = \frac{1}{{1 - \frac{v^{2}}{c^{2}}}}$

$1 - \frac{16}{25} = \frac{v^{2}}{c^{2}}$

$\frac{v}{c} = \sqrt{\frac{9}{25}}$

$\frac{v}{c} = \frac{3}{5}$

$v = \frac{3}{5}c$

6 0

3 years ago

!!!HELP ASAP!!!<br>in witch situation is work being done?<br>theres a photo added.

Arturiano [62]

C..............................

8 0

3 years ago

A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m 14, start fraction, start text, m, en

Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

Change in time

Change in velocity

Δt

−v

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

v, start subscript, f, end subscript, initial velocity v_iv

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

Δt

−v

3.5s

−21

−(−14

)

=−2.0

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0

3 years ago

Engineers and science fiction writers have proposed designing space stations in the shape of a rotating wheel or ring, which wou

lyudmila [28]

Answer:

w = 1.976 rpm

Explanation:

For simulate the gravity we will use the centripetal aceleration $a_c$ , so:

$a_c = w^2r$

where w is the angular aceleration and r the radius.

We know by the question that:

r = 60.5m

$a_c$ = 2.6m/s2

So, Replacing the data, and solving for w, we get:

$2.6m/s = w^2(60.5m)$

W = 0.207 rad/s

Finally we change the angular velocity from rad/s to rpm as:

W = 0.207 rad/s = 0.207*60/(2 $\pi$ )= 1.976 rpm

5 0

3 years ago