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OverLord2011 [107]

3 years ago

5

2x-3=-(4x+9) epic bruh moment,i cant seem to get this right someone please answer it for me.

1 answer:

tatyana61 [14]3 years ago

8 0

Answer: x = -1

Step-by-step explanation:

2x-3= - 4x+9
2x+4x = -9 + 3
6x = -9 + 3
6x/6 = -6/6
x = -1

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A Jerome's rock band recorded 13 songs during an afternoon recording session. Each song took 1/6 of a side of a tape to record.

Lapatulllka [165]

Answer:
number of tape sides = 2.1667 tape sides

Explanation:
We know that each song took 1/6 of a side of tape to be recorded.
To know how many tape sides were used to record 13 songs, all we have to do is cross multiplication as follows:
1 song ..................> 1/6 of a tape side
13 songs ..............> ?? tape sides

Number of tape sides = [(13) * (1/6)] / 1
number of tape sides = 2.1667 tape sides

Hope this helps :)

8 0

3 years ago

Convert standard to slope-intercept forms. 1. Standard form: 10x − 7y = −8

garri49 [273]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Solve 5x^2 − 3x + 17 = 9.

Vedmedyk [2.9K]

Answer:

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

Step-by-step explanation:

To solve:

5x² − 3x + 17 = 9

or

⇒ 5x² − 3x + 17 - 9 = 0

or

⇒ 5x² − 3x + 8 = 0

Now,

the roots of the equation in the form ax² + bx + c = 0 is given as:

x = $\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

in the above given equation

a = 5

b = -3

c = 8

therefore,

x = $\frac{-(-3)\pm\sqrt{(-3)^2-4\times5\times8}}{2\times5}$

or

x = $\frac{3\pm\sqrt{9-160}}{10}$

or

x = $\frac{3+\sqrt{-151}}{10}$ and x = $\frac{3-\sqrt{-151}}{10}$

or

x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

here i = √(-1)

Hence,

The roots of the equation are x = $\frac{3+\sqrt{151}i}{10}$ and x = $\frac{3-\sqrt{151}i}{10}$

and there are no real roots of the equation given above

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Step-by-step explanation:

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