Can car oil degrade carbon fiber?

The rate constant for this second‑order reaction is 0.610 M − 1 ⋅ s − 1 0.610 M−1⋅s−1 at 300 ∘ C. 300 ∘C. A ⟶ products A⟶product

Darya [45]

Answer: It takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.

Explanation:

Integrated rate law for second order kinetics is given by:

$\frac{1}{a}=kt+\frac{1}{a_0}$

k = rate constant = $0.610M^{-1}s^{-1}$

$a_0$ = initial concentration = 0.860 M

a= concentration left after time t = 0.260 M

$\frac{1}{0.260}=0.860\times t+\frac{1}{0.860}$

$t=3.120s$

Thus it takes 3.120 seconds for the concentration of A to decrease from 0.860 M to 0.260 M.

8 0

3 years ago

The molecular weight of vitamin C , C6H8O6 is 176.12 grams over mol

IgorC [24]

Answer:

0.0250 g.

Explanation:

∵ no. of moles (n) = mass / molar mass.

<em>∴ mass of Vitamine C = (n)(molar mass)</em> = (0.000142 mol)(176.12 g/mol) = 0.02501 g = <em>0.0250 g. "three significant figures"</em>

3 0

3 years ago

What is the difference between a homogeneous and a heterogeneous mixture?

Ne4ueva [31]

Answer and explanation :

DIFFERENCE BETWEEN HOMOGENEOUS AND HETEROGENEOUS MIXTURE :

In homogeneous mixture the component which are present in the mixture all are in the same proportion whereas in heterogeneous mixture the component which are present in the mixture don't have the same proportion
We can not pick out the component of homogeneous mixture but in heterogeneous mixture we can pick out the components from the mixture
Example of homogeneous mixture is water, oil ,water sugar solution, milk blood etc. And example of heterogeneous mixture is solution of sand and water ,concrete etc.

7 0

3 years ago

What is the standard enthalpy of a reaction for which the equilibrium constant is (a) doubled, (b) halved when the temperature i

Alexxandr [17]

Answer:

a) 48KJ

b) -48KJ

Explanation:

Given that;

ln(K2/K1) = ΔH°/R(1/T2 - 1/T1)

K2= equilibrium constant at T2

K1 = equilibrum constant at T1

R = gas constant

T1 = initial temperature

T2 = final temperature

When we double the equilibrium constant K1; K2 = 2K1

T1 = 310 K

T2 = 310 + 15 = 325 K

ln(2K1/K1) =- ΔH°/R(1/T2 - 1/T1)

ln2 = -ΔH°/8.314(1/325 - 1/310)

0.693 = -ΔH°/8.314(3.08 * 10^-3 - 3.2 * 10^-3)

0.693 = -ΔH°/8.314 (-0.00012)

0.693 = 0.00012ΔH°/8.314

0.693 * 8.314 = 0.00012ΔH°

ΔH° = 0.693 * 8.314/0.00012

ΔH° = 48KJ

b) K2 =K1/2

ln(K1/2/K1) =- ΔH°/R(1/T2 - 1/T1)

ln (1/2) = -ΔH°/8.314 (1/325 - 1/310)

-0.693 = -ΔH°/8.314 (-0.00012)

-0.693 = 0.00012ΔH°/8.314

-0.693 * 8.314 = 0.00012ΔH°

ΔH°= -0.693 * 8.314/0.00012

ΔH°= -48KJ

6 0

3 years ago

Find the density of a material given that a 5.03g sample occupies 3.24ml

Verizon [17]

Formula for density:

D = Mass / Volume

Mass = 5.03g

Volume = 3.24ml

Formula in our case:

D = 5.03 / 3.24

$D = 0.31~g/m^{3}$

Hope it helped,

BioTeacher101

3 0

3 years ago

Can car oil degrade carbon fiber?​

Can car oil degrade carbon fiber?