The power expended is 500 W
Explanation:
First of all, we start by calculating the work done by the man in order to ascend: this is equal to the gravitational potential energy gained by the man, which is
where
m = 50 kg is the mass of the man
is the acceleration of gravity
is the change in height
Substituting,
Now we can calculate the power expended, which is given by
where
W = 2500 J is the work done
t = 5 s is the time elapsed
Substituting, we find
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ANSWER: A ramp meter, usually is a basic traffic light or a two-section signal light, together with a signal controller, that regulates the flow of traffic that enters freeways according to the most traffic conditions.
Responder:
Fb = 17,5 kN
Explicación:
La expresión de la fuerza de empuje
Fb = ρgV ---------- 1
dónde
Fb = fuerza de flotación
ρ = densidad del fluido
g = aceleración debida a la gravedad
V = volumen de fluido
Paso uno:
datos dados
radio del cilindro = 0,3 m
altura h = 8m
densidad = 790 kg / m ^ 3
g = 9,8 m / s ^ 2
El volumen del cilindro se expresa como
V = πr ^ 2h
V = 3,142 * 0,3 ^ 2 * 8
V = 3,142 * 0,09 * 8
V = 2,26
El volumen es 2.26m ^ 3, el volumen del cilindro es igual al volumen de alcohol disparado
La expresión de la fuerza de empuje es
Fb = ρgV
sustituyendo tenemos
Fb = 790 * 9,8 * 2,26
Fb = 17514,26N
Fb = 17,5 kN
Hello,
The exosphere is the lowest<span> in density of the </span>layers of the atmosphere.
The higher up you get into the atmosphere, the lower the density becomes. Thus, the troposphere has the highest density of the five layers.
Faith xoxo
Answer:
The value of gauge pressure at outlet = -38557.224 pascal
Explanation:
Apply Bernoulli' s Equation
+ 
+ 
= 
+ 
+ 
--------------(1)
Where
= Gauge pressure at inlet = 3.70105 pascal
= velocity at inlet = 2.4 
= Gauge pressure at outlet = we have to calculate
= velocity at outlet = 3.5
= 3.6 m
Put all the values in equation (1) we get,
⇒ 
+ 
= + 
+ 3.6
⇒ 0.294 = + 0.6244 + 3.6
⇒ = 0.294 - 0.6244 - 3.6
⇒ = - 3.9304
⇒ = - 38557.224 pascal
This is the value of gauge pressure at outlet.
