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garik1379 [7]
3 years ago
10

9p + 8 Math fraction

Mathematics
1 answer:
Klio2033 [76]3 years ago
8 0

Answer:

17p

Step-by-step explanation:

9p+8p=17p

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bixtya [17]

Answer: x=5, y=22 C.

Step-by-step explanation:

I just did the quiz

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3 years ago
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HELP WITH NUMBER 13 please
amid [387]

Answer: QE = 10

Step-by-step explanation: To solve this problem, it's important to understand that the diagonals of a parallelogram bisect each other.

This means that E is the midpoint of diagonal SQ.

So we can setup the equation x² + 9x = 4x + 6.

To solve this polynomial equation, set it equal to zero first.

So we have x² + 5x - 6 = 0 and we get (x + 6)(x - 1) = 0

when we factor the left side of the equation.

So this means that x = -6 or x = 1.

However, -6 will give us a negative length when we plug it in

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4 0
2 years ago
PLEASE HELP ME!!!!!
Vlada [557]

Answer:

I'm not 100% sure but I believe the answer is A

4 0
2 years ago
<img src="https://tex.z-dn.net/?f=g%28x%29%20%3D%203x%20-%206" id="TexFormula1" title="g(x) = 3x - 6" alt="g(x) = 3x - 6" align=
VARVARA [1.3K]

Hey there! :)

Answer:

g^{-1} (g(10))=10

Step-by-step explanation:

Begin by calculating g(10):

g(x) = 3x - 6

Substitute in 10 for x:

g(10) = 3(10) - 6

g(10) = 30-6

g(10) = 24.

Plug '24' into 'x' into g^{-1} (x)

g^{-1} (24)=\frac{(24) + 6}{3}

Simplify:

g^{-1} (24)=\frac{30}{3}

g^{-1} (24)=10

3 0
3 years ago
Which of the following statements is not true? a) The standard deviation of the sampling distribution of sample mean = σ/√n b) T
I am Lyosha [343]

Answer:

e) The mean of the sampling distribution of sample mean is always the same as that of X, the distribution from which the sample is taken.

Step-by-step explanation:

The central limit theorem states that

"Given a population with a finite mean μ and a finite non-zero variance σ2, the sampling distribution of the mean approaches a normal distribution with a mean of μ and a variance of σ2/N as N, the sample size, increases."

This means that as the sample size increases, the sample mean of the sampling distribution of means approaches the population mean.  This does not state that the sample mean will always be the same as the population mean.

6 0
3 years ago
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