It is supernova! :D
A supernova is an astronomical concussion that momentarily surpasses the whole universe, emitting as many energy since the Day-Star(sun) practically any normal star is supposed to release across its whole lifespan, before it disappears from appearance over some weeks or periods.
Answer: the frequency observed will be 1269.45hz
Explanation: according to the doppler effect,
Apparent frequency f' = (c/(c+u))*f
f = real freq of sound of moving sound source
c = speed of sound in air
u = speed of moving sound source
f' = (343/(343+33.6))*1395
f' = 1269.45hz
Angular width is 3 x 10^-3
Let D be the distance between source and screed d the distance between coherent source then for central diffraction maxima,
where λ is wavelength
Given:
λ = 450 nm = 450×10^−9m
d = 0.3x10^−3m, D = 1m
W = 2 x 450×10^−9/0.3x10^−3*1
To Find:
Angular width
Solution: The width of the central maxima is nothing but the difference between the positions of the first two minima. Hence we will use the expression for the position of minima and accordingly obtain the expression of the width of central maxima and secondary maxima
θ = W/D
θ = 2 x 450×10^−9/0.3x10^−3*1/1 = 3 x 10^-3
Hence, angular width is 3 x 10^-3
Learn more about Angular width here:
brainly.com/question/25292087
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We have:
s=3,7km (3700m)
u=0
v=26m/s
a=
t=
We look up for a formula to solve for a:
v²=u²+2as u²=0 so
v²=2as
(26m/s)²=2a3700m
676/7400=a
a=0,09m/s²
