What is the impulse needed to stop a 45-kg boy who is running at 6 m/s in 3 seconds?

Physics

1 answer:

Tju [1.3M]3 years ago

6 0

Impulse = change of momentum
Impulse = 45 x 6 = 270 Ns

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A pebble is thrown into the air with a velocity of 19/m at an angle of 36 with respect to the horizontal.

kow [346]

Answer:

The maximum height the pebble reaches is approximately;

A. 6.4 m

Explanation:

The question is with regards to projectile motion of an object

The given parameters are;

The initial velocity of the pebble, u = 19 m/s

The angle the projectile path of the pebble makes with the horizontal, θ = 36°

The maximum height of a projectile, $h_{max}$ , is given by the following equation;

$h_{max} = \dfrac{\left (u \times sin(\theta) \right)^2}{2 \cdot g}$

Therefore, substituting the known values for the pebble, we have;

$h_{max} = \dfrac{\left (19 \times sin(36 ^{\circ}) \right)^2}{2 \times 9.8} = 6.3633894140470403035477570509439$

Therefore, the maximum height of the pebble projectile, $h_{max}$ ≈ 6.4 m.

3 0

3 years ago

what is the percent efficiency of a light bulb that emits 14 joules of light for every 60 joules of electric energy thst enters

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If you're using the bulb as a source of light, then it's. 14/60 = 23.3% efficient.
If you're using it to heat a bird nest or a hamster cage, then it's. 46/60 = 76.7% efficient !
It just depends on your point of view, and what you consider 'useful' output.

5 0

3 years ago

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Studentka2010 [4]

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A uniform magnetic field B=5.210 T is perpendicular to the plane of the paper (into the page). The current-carrying wire of valu

ehidna [41]

Answer:5.21 N

Explanation:

Given