Answer:
3.
D. Philippine Atmospheric, Geophysical and Astronomical Services
Administration (PAGASA)
Explanation:
4.C. 62.0 kph
Answer:
0.774g of ethanol
0.970mL of ethanol
Explanation:
Molality is an unit of concentration defined as the ratio between moles of solute and kg of solvent.
In the problem, you need to prepare a 1.2m solution of ethanol (Solute) in t-butanol (solvent).
14.0g of butanol are <em>0.014kg </em>and as you want to prepare the 1.2m solution, you need to add:
0.014kg × (1.2moles / kg) = 0.0168 moles of solute = Moles of ethanol
To convert moles of ethanol to mass you require molar mass (Molar mass ethanol, C₂H₅OH = 46.07g/mol). Thus, mass of 0.0168 moles are:
0.0168moles Ethanol ₓ (46.07g / mol) =
<h3>0.774g of ethanol</h3>
And to convert mass in g to mL you require density of the substance (Density of ethanol = 0.798g/mL):
0.774g ₓ (1mL / 0.798g) =
<h3>0.970mL of ehtanol</h3>
It’s either the first or second one
I think it’s the first one - the outer cells of the blastocyst
Answer:
Explanation:
according to balance chemical equation
3 A2 moles produced 2 moles of A3B
so 12 moles A2 will produced moles of A3B= 12*2/3=24/3= 8
therefore 12 moles of A2 produced 8 moles of A3B