Ask question

Ask question

All categories

3 years ago

5

Which one of the following best represents the predicted approximate chemical shift and coupling:

1 answer:

mezya [45]3 years ago

4 0

Answer:

C. 3.40 ppm, singlet

Explanation:

Given the information from the question .we have to select the best representation for represents the predicted approximate chemical shift and coupling for hydrogen(s). In this case, there is no neighboring hydrogen .Thus there won’t be any split .the best option answer is C. 3.40 ppm, singlet . Therefore the correct answer or option is C. 3.40 ppm, singlet.

You might be interested in

Mn2(CO3)3 what is the cation and anion in this compound?

brilliants [131]

Mn+2 is cation and CO3 is anion
hope it help

7 0

3 years ago

Read 2 more answers

3. Use the chart to answer the following question. Amanda found a stone

REY [17]

Answer:

Quartz

Explanation:

6 0

3 years ago

Which of these statements is true about the temperature of a substance?

Svetradugi [14.3K]

Answer:

(c)

Explanation:

4 0

3 years ago

What is the mass of 19.5 moles of carbon dioxide?

Olenka [21]

Explanation:

mass = moles * molar mass

molar mass of carbon dioxide (CO2) = 12+32 = 44

= 19.5* 44 = 858

proof

moles = mass /molar mass

= 858/44 = 19.5 moles

6 0

3 years ago

What expression approximates the volume of O2 consumed, measure at STP, when 55 g of Al reacts completely with excess O2?2 Al(s)

Genrish500 [490]

Answer:

34.28 L ( 1.5*22.4 L)

Explanation:

Calculation of the moles of aluminum as:-

Mass = 55 g

Molar mass of aluminum = 26.981539 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Moles= \frac{55\ g}{26.981539\ g/mol}$

$Moles= 2.0384\ mol$

According to the reaction:-

$4Al+3O_2\rightarrow 2Al_2O_3$

4 moles of aluminum react with 3 moles of oxygen gas

1 mole of aluminum react with $\frac{3}{4}$ moles of oxygen gas

2.0384 moles of aluminum react with $\frac{3}{4}\times 2.0384$ moles of oxygen gas

Moles of oxygen gas = 1.5288 moles

At STP,

Pressure = 1 atm

Temperature = 273.15 K

Using ideal gas equation as:

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

1 atm × V = 1.5288 mol × 0.0821 L.atm/K.mol × 273.15 K

⇒V = 34.28 L ( 1.5*22.4 L)

7 0

3 years ago