Answer:
Te is considered a Group A element.
Explanation:
Fe, Hg and Y belong to Group B.
U is a transition element.
<em>Te is the only element that belong to Group A.</em>
I hope I've solved your doubt.
Answer:
B.Handling the crucible directly with your hands.
D.Taking the mass of the empty crucible without the lid, but including the lid in all other mass measurements.
E.Taking the mass of all samples with the lid included.
Explanation:
When observed critically , the measures associated with the errors which could cause your percent yield to be falsely high, or even over 100% are those which increase the weight of the substance with the individual neglecting.
Handling the crucible directly with your hands,Taking the mass of the empty crucible without the lid, but including the lid in all other mass measurements and taking the mass of all samples with the lid included will all increase the weight of the substance. Instead the substance should be placed alone without any form of support or contamination.
Answer:
Explanation:
Basically in metallic bonds, valence electrons are not localied which means they can freely move from one atom to another. Thus, they move in "sea of electrons" because in a sea water or waves are freely moving without any localization.
Hope that helps.
Answer:
c. 3 atm
Explanation:
First, we will use the ideal gas equation to find the moles of each gas.
N₂(g)
P × V = n × R × T
n = P × V / R × T
n = 1 atm × 2 L / (0.082 atm.L/mol.K) × 273 K
n = 0.089 mol
Ar(g)
P × V = n × R × T
n = P × V / R × T
n = 1 atm × 1 L / (0.082 atm.L/mol.K) × 273 K
n = 0.045 mol
The total gaseous moles are 0.089 mol + 0.045 mol = 0.134 mol
Now, we will use the ideal gas equation to find the pressure of the gaseous mixture.
P × V = n × R × T
P = n × R × T / V
P = 0.134 mol × (0.082 atm.L/mol.K) × 273 K / 1 L
P = 3 atm
May be it will be silver because they are in same level in chemical activity series
