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3 years ago

What engine thrust is required for a rocket of mass 35 kg to leave the launching pad? 3.5 N. 35 N. 351 N. 3,500 N. 35,000 N.

1 answer:

7 0

In order for the object to move upward, it needs an upward force
that's at least equal to its own weight.

Weight = (mass) x (gravity) = (35 kg) x (9.8 m/s²) = 343 N.

The engine thrust has to be more than 343 N.

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You drive 4 km at 30 km/h and then another 4 km at 50 km/h. What is your average speed for the whole 8-km trip?

Setler79 [48]

Answer:

option A

Explanation:

given,

drive 4 km at 30 km/h and

another 4 km at 50 km/h

average speed for the whole 8 Km trip = ?

time for the trip of first 4 km

distance = speed x time

$t_1 = \dfrac{d}{s}$

$t_1 = \dfrac{4}{30}$

t₁= 0.1333 hr

time from another 4 km trip

$t_2 = \dfrac{d}{s}$

$t_2= \dfrac{4}{50}$

t₂ = 0.08 hr

average speed

$s= \dfrac{d}{t}$

$s= \dfrac{8}{0.1333 + 0.08}$

$s= \dfrac{8}{0.2133}$

s = 37.50 Km/hr

Less than 40 Km/h

the correct answer is option A

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3 years ago

The net flow of energy into and out of the earths system is referred to as energy budget. which type of energy is lost in space

Svet_ta [14]

D not 100% sure though.

4 0

3 years ago

Select the correct answer.

mrs_skeptik [129]

Answer:

Explanation:

net force = right force - left force

net force = 22 - 13=9N

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3 years ago

A city planner is working on the redesign of a hilly portion of a city. An important consideration is how steep the roads can be

Artyom0805 [142]

Explanation:

It is known that relation between force and acceleration is as follows.

F = $m \times a$

I is given that, mass is 1090 kg and acceleration is 21 m/s. Therefore, we will calculate force as follows.

F = $m \times a$

= $1090 \times (\frac{21}{16})$

= 1430.625 N

Also, it is known that

$sin(\theta) = \frac{\text{Force car can exert}}{\text{Force gravity pulls car}}$

$sin(\theta) = \frac{1430.625 N}{(1090 \times 9.8) N}$

$\theta$ = 7.70 degrees

Thus, we can conclude that the maximum steepness for the car to still be able to accelerate is 7.70 degrees.

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Diano4ka-milaya [45]

Answer:

Because this pole is different from the original pole that magnetized the paperclips, the top paperclip will become demagnetized in the opposite direction and the bottom paperclip will be repelled away

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3 years ago