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Over [174]
3 years ago
15

A car in motion has kinetic energy. What happens to the kinetic energy when the car brakes to a stop? The kinetic energy is tran

sformed into potential energy ready to be released when the car starts back up. The kinetic energy is lost since energy is not conserved. The kinetic energy is transformed into heat energy evident by the warmth of the tires and is dissipated. The kinetic energy is still there, it is just not observable.
Physics
1 answer:
Pie3 years ago
7 0

Answer:

<em>When a moving car brakes to a stop the </em><em>kinetic energy of the car is converted to heat energy. </em>

Explanation:

A moving car has kinetic energy.

It is given by the equation k=\frac{1}{2} mv^2

Where m denotes mass of the car and v denote sits velocity. When the brakes are applied the velocity becomes zero and the car doesn’t possess kinetic energy anymore.

According to law of conservation of energy can neither be created nor be destroyed but can only be transformed from one form to another. On coming to a stop,  the kinetic energy of the car  gets converted to heat. The friction between the tyre and the road heats up the tyre.

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A butterfly flies from the top of a tree in the center of a garden to rest on top of a red flower at the garden's edge. The tree
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The butterfly takes a vertical perpendicular path equivalent to 9m and travels a horizontal distance of 17m. The net path between the two is equivalent to that of the hypotenuse, so we will apply the Pythagorean theorem.

x=\sqrt{(9)^2+(0.17)^2}

x = 9.0061 \approx 9.0 m

Therefore the magnitude of the butterfly's displacement is 9m

3 0
3 years ago
Read 2 more answers
The two blocks in oscillate on a frictionless surface with a period of 1.5 s. The upper block just begins to slip when the ampli
Setler79 [48]

Answer:

0.72

Explanation:

T = Time period of oscillation = 1.5 s

Angular frequency is given as

w = \frac{2\pi }{T}\\w = \frac{2(3.14) }{1.5}\\w = 4.2 rad/s

A = Amplitude of oscillation = 40 cm = 0.40 m

\mu = Coefficient of static friction = ?

a = acceleration of the block

m = mass of the block

Maximum acceleration of the block is given as

a = Aw^{2}

frictional force is given as

f = \mu mg

As per newton's second law

f = ma \\\\\mu mg = ma \\\mu g = a\\\mu g = Aw^{2}\\\mu (9.8) = (0.40)(4.2)^{2}\\\mu = 0.72

8 0
3 years ago
At the 1 s mark, which objects have equal momentum?
Rudik [331]
C. The bowling ball and the bicycle

p = mv
P of bike = 12x5 = 60
P of rock = 2x20 = 40
P of ball = 5 x 10 = 60
3 0
3 years ago
Roots show ____. geotropism because they grow toward gravitational pull. 1.) positive 2.) neutral 3.) negative 3.)
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Its the second option if you have Suttons Bay Virtual Online School

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3 years ago
A person who normally weighs 700 N is riding in an elevator that is moving upward but slowing down at a steady rate. If this per
xz_007 [3.2K]

Answer:

The scale will read less than 700 N

Explanation:

Given;

normal weight of the person, W = 700 N

The upward acceleration of the elevator is given by Newton's second law of motion;

F = ma

Also, the weight of the person, W = mg

Net force on the person when the elevator accelerates upward is given as;

R = ma + mg

When the elevator slows down at a steady rate, then net force on the person is given as;

R = mg - ma

R = m(g - a), this net force on the person is also the reading of the scale.

Thus, the scale will read less than 700 N.

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2 years ago
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