W = Fd = 4(2100) = 8400 J
So the answer is A) 8400 J
I was just rewriting my notes on the work lesson I did in class today, so I saw this question at the perfect time!! :)
Hope it helps!! :)
20m away
the dog was 60m away from. you subtract 40m since it is 10m/s x 4 seconds
Answer:
u = 11.6 m/s
Explanation:
The end of a launch ramp is directed 63° above the horizontal. A skier attains a height of 10.9 m above the end of the ramp.
Maximum height, H = 10.9
Let v is the launch speed of the skier. The maximum height attained by the projectile is given by :


u = 11.6 m/s
So, the launch speed of the skier is 11.6 m/s. Hence, this is the required solution.
I found this!! maybe this will help :)
Answer:
TATTCATTCATTA—TGATTT—ATTCG
Explanation:
A mutation is a permanent change in the nucleotide sequence of DNA. A mutation occurs during replication or recombination. It may be due to base substitutions, deletions and insertions. As per the question, DNA segment forms encodes for the enzyme pepsin is CATTGTTA.
Option TATTCATTCATTA—TGATTT—ATTCG is the correct answer. In the DNA segment which encodes pepsin, a purine base (G) guanine is replaced by another purine (A) adenine. This type of mutation is called a transition type point mutation.
Due to base substitution, the mutated segment CATTCATTA will nor encode pepsin.