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4 years ago

13

Why is it possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball?

1 answer:

bulgar [2K]4 years ago

7 0

It is possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball, because the 0.145 kg baseball is of a smaller mass than the 7 kg bowling ball and it also offers less resistance to motion and hence it would go further than the 7 kg bowling ball.

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Un resorte se alarga 5 cm bajo la acción de una fuerza de 39,2 N. ¿Cuál es la constante del resorte? Si ahora la fuerza es 68,6

Lorico [155]

Answer:

$k=784 N/m$

$\Delta x=8,8 cm$

Explanation:

Usando la ley de Hook tenemos:

$F=k\Delta x$

Solving it for k we have:

$k=\frac{F}{\Delta x}$

$k=\frac{39,2}{0,05}$

$k=784 N/m$

Usando la misma ecuación y sabiendo k tenemos:

$\Delta x=\frac{F}{k}$

$\Delta x=\frac{68,6}{784}$

$\Delta x=8,8 cm$

Espero esto te ayude!

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3 years ago

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Alekssandra [29.7K]

is the horse running/moving? if so then kinetic i believe

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3 years ago

A wagon wheel consists of 8 spokes of uniform diameter, each of mass ms and length L cm. The outer ring has a mass mring. What i

just olya [345]

Answer:

The moment of inertial of the wheel, $I = 8(\frac{1}{3}M_sL^2 ) + M_rL^2$

Explanation:

Given;

8 spokes of uniform diameter

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length of each spoke, = L

mass of outer ring, = $M_r$

The moment of inertial of the wheel will be calculated as;

$I = 8I_{spoke} + I_{ring}$

where;

$I_{spoke$ is the moment of inertia of each spoke

$I_{ring$ is the moment of inertia of the rim

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Moment of inertial of the wheel

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3 years ago

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Molodets [167]

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Explanation:

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so ω= 2 π/3600 rad/s

Now linear velocity v= r ω

r= radius of minute hand=14 cm

so v= 14 (2 π/3600)

V=0.0244 cm/s

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3 years ago

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jeyben [28]

Answer:

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3 years ago