All categories

3 years ago

Why is it possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball?

1 answer:

7 0

It is possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball, because the 0.145 kg baseball is of a smaller mass than the 7 kg bowling ball and it also offers less resistance to motion and hence it would go further than the 7 kg bowling ball.

You might be interested in

A person with a gravitational force of 750 N is sitting in the centre of a hammock which is strung between two trees. The ropes

bija089 [108]

Answer:

Answer in photo

Explanation:

Answer in photo

8 0

2 years ago

Question 11

notka56 [123]

The volume of the gas once it reaches the surface of water is 2 liters.

The volume of the air in balloon at depth of 100ft (30m) is 500ml.

The pressure at this point is 4 atm.

Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.

The pressure at the surface of water is 1 atms.

As we know, from the ideal gas equation,

PV = nRT

Where,

P is the Pressure of gas,

V is the volume of the gas,

n is the number of moles,

R is the gas constant whose value is 0.082057 L atm mol-1 K-1,

T is the temperature.

Assuming that the temperature is constant,

We know,

PV = nRT

All quantities on the right side are constants,

So, we can write,

P₁V₁ = P₂V₂

Putting all the the values,

4(0.5) = 1V₂

V₂ = 2 Liters.

The volume of the air at the surface is 2 liters.

1 liter = 0.001 m

Hence,

2 liters = 0.002 m³

So the volume of air at the surface is 0.002m³.

To know more about Ideal gas Equation, visit,

brainly.com/question/20348074

#SPJ9

3 0

1 year ago

Conveyor belts are often used to move packages around warehouses. The conveyor shown below moves packages at a steady 4.0 m/s. A

Alisiya [41]

Answer:

0 j

Explanation:

4 0

3 years ago

What is the maximum value of the magnetic field at a<br> distance2.5m from a 100-W light bulb?

MA_775_DIABLO [31]

To solve this problem we will apply the concepts related to the intensity included as the power transferred per unit area, where the area is the perpendicular plane in the direction of energy propagation.

Since the propagation occurs in an area of spherical figure we will have to

$I = \frac{P}{A}$