Why is it possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball?

1 answer:

7 0

It is possible to throw a 0.145 kg baseball much further than a 7 kg bowling ball, because the 0.145 kg baseball is of a smaller mass than the 7 kg bowling ball and it also offers less resistance to motion and hence it would go further than the 7 kg bowling ball.

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Suppose that at room temperature, a certain aluminum bar is 1.0000 m long. The bar gets longer when its temperature is raised. T

raketka [301]

Answer:

ΔL =0. 000312 m

Explanation:

Given that

At room temperature ( T = 25 ∘C) ,L= 1 m

$L=1+2.4\times 10^{-5}T$

So the length at 13.0 ∘C above room temperature

$L=1+2.4\times 10^{-5}T$

$L=1+2.4\times 10^{-5}\times 13$

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So the change in length

ΔL = 1.000312 - 1.0000 m

ΔL =0. 000312 m

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A circular loop of radius r carries a current i. at what distance along the axis of the loop is the magnetic field one-half its

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At r = 0.766 R the magnetic field intensity will be half of its value at the center of the current carrying loop.

We have a circular loop of radius ' r ' carrying current ' i '.

We have to find at what distance along the axis of the loop is the magnetic field one-half its value at the center of the loop.

<h3>What is the formula to calculate the Magnetic field intensity due to a current carrying circular loop at a point on its axis?</h3>

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$B(x) = \frac{\mu_{o} iR^{2} }{2(x^{2} +R^{2})^{\frac{3}{2} } }$