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Marianna [84]
3 years ago
7

The instantaneous velocity of an object is the Blank of the object with a Blank.

Physics
1 answer:
Ghella [55]3 years ago
8 0
The intaneuos velocity of an object is the
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3 years ago
A metallic sheet has a large number of slits, 5.0 mm wide and 20 cm apart, and is used as a diffraction grating for microwaves.
san4es73 [151]

To solve this problem it is necessary to apply the concepts related to the principle of superposition and constructive interference, that is to say everything that refers to an overlap of two or more equal frequency waves, which when interfering create a new pattern of waves of greater intensity (amplitude) whose cusp is the antinode.

Mathematically its definition can be given as:

d sin\theta =m\lambda

Where

d = Width of the slit

\theta = Angle between the beam and the source

m = Order (any integer) which represent the number of repetition of the spectrum, at this case 1 (maximum respect the wavelength)

Since the point of the theta angle for which the diffraction becomes maximum will be when it is worth one then we have to:

\lambda = d

\lambda = 20cm = 20*10^{-2}m

Applying the given relation of frequency, speed and wavelength then we will have that the frequency would be:

f = \frac{v}{\lambda}

Here the velocity is equal to the speed of light and the wavelength to the value previously found.

f = \frac{3*10^8}{0.2}

f = 1.5Ghz

Therefore the smallest microwave frequency for which only the central maximum occurs is 1.5Ghz

7 0
3 years ago
The bones of the forearm (radius and ulna) are hinged to the humerus at the elbow. The biceps muscle connects to the bones of th
SVETLANKA909090 [29]

Answer:

F_b  = 1647.92 N

Explanation:

Given:

length of the arm, r = 0.465 m

distance of forearm from elbow, r' = 2.15 cm = 0.0215 m

Mass of the forearm, M = 2.45 kg

Mass of the object, m = 6.55 kg

Let, the Force by bicep be, F_b

under the motionless condition, the net moment about elbow is zero

thus,

F_b × 0.0215 - Mg × (0.465/2) - mg × (0.465) = 0

or

F_b × 0.0215 - 2.45 × 9.8 × (0.465/2) - 6.55 × 9.8 × (0.465) = 0

or

F_b × 0.0215 - 5.582 - 29.848 = 0

or

F_b  = 1647.92 N

hence, the force exerted by the elbow is 1647.92 N

4 0
3 years ago
Read 2 more answers
Which examples are a COMPLETE description of motion? Select ALL that apply.
SIZIF [17.4K]
All of them apply because they all are doing some thing to move
8 0
2 years ago
Dont know whether its b or c. (cuz for sure it transports energy)
masha68 [24]

Sound waves are a type of classical waves and so they transport only energy without transporting matter through the medium.

6 0
3 years ago
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