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Nesterboy [21]
4 years ago
15

a 2.43g sample of MgSO4 hydrate (MGSO4 * x H2O) is heated and 1.19g of anhydrous MGSO4 remains. Calculate the miles of water (x)

per 1 mole of MgSO4.
Chemistry
2 answers:
Anna007 [38]4 years ago
5 0

Explanation

Part A: 0.0201

Part B: 2.51g

Part C: 0.1393

Part D: 7:1

Part E: 7

mars1129 [50]4 years ago
4 0
Answer is: ratio of water and magnesium sulfate is 7 : 1.
m(MgSO₄ · xH₂O) = 2,43 g.
m(MgSO₄) = 1,19 g.
m(H₂O) = 2,43 g - 1,19 g.
m(H₂O) = 1,24 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 1,24 g ÷ 18 g/mol.
n(H₂O) = 0,069 mol.
n(MgSO₄) = m(MgSO₄) ÷ M(MgSO₄).
n(MgSO₄) = 1,19 g ÷ 120,36 g/mol.
n(MgSO₄) = 0,0099 mol.
n(MgSO₄) : n(H₂O) = 0,0099 mol : 0,069 mol.
n(MgSO₄) : n(H₂O) = 1 : 7.

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How many silver atoms are there in 3.78g of silver?
oksian1 [2.3K]

2.1 x 10²²atoms

Explanation:

Given parameters:

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Unknown:

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Solution:

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8 0
3 years ago
How much water can be produced from the complete reaction of 3.84 l of oxygen gas, at stp, with hydrogen gas? answer in units of
Marysya12 [62]
First, write a balanced chemical equation:

2H2(g) + O2(g) --> 2H2O(l)

We are given that oxygen has a volume of 3.84L, so we need to use the formula n = V / MV 

As mentioned, at stp, so MV= 24.79

n = 3.84 / 24.79
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The ratio of oxygen to water is 1:2, therefore we need to multiply the moles found by 2 to gain the moles of water,

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Use the formula n = m / M, where m is mass and M is molar mass

0.3098.. = m / (2(1.008) + 2(16))
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Therefore, 10.54g of water is produced (2 d.p)

HOPE THIS HELPED!
6 0
4 years ago
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