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liraira [26]
3 years ago
13

Kamala puts on inline skates and stands facing a wall. When she pushes against the wall, she rolls backward. Why does pushing ha

rder make her roll faster?
-The force of friction between the wheels and the ground decreases.

-The force of the wall pushing on her increases.

-The additional force decreases her weight.

-The extra force causes an increase of the normal force from the ground.
Physics
2 answers:
Veseljchak [2.6K]3 years ago
8 0

Because the force of the wall pushing on her increases.

According to Newton's third law of motion, to every action there is an equal and opposite reaction. When the Kamala pushes the wall, the wall also pushes her. Pushing harder against the wall causes the force of the wall pushing her also increase. Thus, making her roll faster.

Svetach [21]3 years ago
7 0

Answer: Second option "The force of the wall pushing on her increases."

Explanation: This is because of Newton's third law: For every action (force) in nature, there is an equal and opposite reaction.

So when Kamala pushes against the wall, the wall is also pushing against Kamala, and this is what impulses her backward. So if she uses more force, then the wall sill apply more force on her, and then she will roll faster.

The right answer is then the second option: "The force of the wall pushing on her increases."

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kkurt [141]

Answer:

(a) 1462.38 m/s

(b) 2068.13 m/s

Explanation:

(a)

The Kinetic energy of the atom can be given as:

K.E = (3/2)KT

where,

K = Boltzman's Constant = 1.38 x 10⁻²³ J/k

K.E = Kinetic Energy of atoms = 343 K

T = absolute temperature of atoms

The K.E is also given as:

K.E = (1/2)mv²

Comparing both equations:

(1/2)mv² = (3/2)KT

v² = 3KT/m

v = √[3KT/m]

where,

m = mass of Helium = (4 A.M.U)(1.66 X 10⁻²⁷ kg/ A.M.U) = 6.64 x 10⁻²⁷ kg

v = RMS Speed of Helium Atoms = ?

Therefore,

v = √[(3)(1.38 x 10⁻²³ J/K)(343 K)/(6.64 x 10⁻²⁷ kg)]

<u>v = 1462.38 m/s</u>

(b)

For double temperature:

T = 2 x 343 K = 686 K

all other data remains same:

v = √[(3)(1.38 x 10⁻²³ J/K)(686 K)/(6.64 x 10⁻²⁷ kg)]

<u>v = 2068.13 m/s</u>

8 0
3 years ago
An object with a higher temperature can have less thermal energy than an object
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It’s true, because it also depends on things like mass. Higher temperature but less mass< Lower temperature but more mass.
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Given:

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Let's find the net centripetal force exterted on the ball.

Apply the formula:

\sum ^{}_{}F_{\text{net}}=F_1+F_2=F_{centripetal}

From the given figure, the force acting towards the circular path will be positive, while the force which points directly away from the center is negative.

Hence, the tensional force is positive while the gravitational force is negative.

Thus, we have:

F_{\text{net}}=F_{\text{centripetal}}=F_{tension}-F_{gravity}=25N-10N=15N

Therefore, the net centripetal force exterted on the ball is 15 N.

ANSWER:

15 N

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