Answer:Cm=o,4 (Mol/l)
Explanation:
Ca(OH)2(s) + 2HCl(aq) → CaCl2(aq) + H2O(l)
0,01 0,02
CM=n/V
<h3>Answer:</h3>
The starting material involved in the formation of 5-Oxoheptanal is 1-ethylcyclopent-1-ene as shown in reaction below.
<h3>Explanation:</h3>
Ozone is one of the reactive allotrope of oxygen. It reacts vigorously with unsaturated compounds like alkenes and alkynes. In this reaction alkene and O₃ first react to produce Molozonide which is highly unstable and rearranges to form a stable ozonide as shown in scheme attached below.
Furthermore, the ozonide on reduction is convertwed into ketones and aldehydes respectively.
Explanation:
Large hydrocarbon molecules can be cracked in an oil refinery through the process of cracking. Cracking of hydrocarbons involves the use of heat, pressure and catalyst to resolve heavy hydrocarbons into simpler and more useful products.
- Cracking of hydrocarbons is very essential in the oil refinery.
- Cracking helps to break giant hydrocarbon molecules into simple and more useful ones.
- Fractional distillation separates oil molecules into its different components based on their different boiling points.
- The fractions produced a times are usually long chained and are not in high demand.
- Catalytic cracking and thermal cracking helps to break the long chains of the heavy hydrocarbons fractions into simpler ones.
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Answer:
For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
Explanation:
<u>Step 1: </u>Data given
Number of moles of Pb(ClO2)2 = 1
Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1
So to bind we should have <u>twice</u> ClO2
1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*<u>2</u>= 2 moles of Cl and 2*<u>2</u> = 4 moles of 0.
This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).
