Question

The length of a bicycle pedal arm is 0.152 m, and a downward force of 118 N is applied to the pedal by the rider's foot. What is the magnitude of the torque about the pedal arm's pivot point when the arm makes the following angles with the vertical? (a) 30°

Answer 1

Answer:8.968 N-m

Explanation:

Given

Length of arm=0.152 m

Downward force=118 N

angle made by arm with vertical$=30^{\circ}$

Force can be divided into two components

It's sin component will contribute towards torque while cos component will not contibute

$Torque =Fsin30\times L$

$T=118\times sin30\times 0.152$

T=8.968 N-m