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Gennadij [26K]
3 years ago
11

The length of a bicycle pedal arm is 0.152 m, and a downward force of 118 N is applied to the pedal by the rider's foot. What is

the magnitude of the torque about the pedal arm's pivot point when the arm makes the following angles with the vertical? (a) 30°
Physics
1 answer:
Veseljchak [2.6K]3 years ago
5 0

Answer:8.968 N-m

Explanation:

Given

Length of arm=0.152 m

Downward force=118 N

angle made by arm with vertical=30^{\circ}

Force can be divided into two components

It's sin component will contribute towards torque while cos component will not contibute

Torque =Fsin30\times L

T=118\times sin30\times 0.152

T=8.968 N-m

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Answer:

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Explanation:

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3 years ago
This problem is based on the whole idea of pressure but I’m having trouble on when the area circle formula is included.
Mice21 [21]

Answer:

6.23x10^6Pa

Explanation:

Data obtained from the question include:

F (force) = 490N

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First, we'll begin by calculating the area of the circlular heel. This is illustrated below:

Area of circle = πr^2

Area = 22/7 x (0.00)^2

Area = 7.86x10^-5m^2

Pressure is simply force per unit area. It represented mathematically as

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Pressure = 6.23x10^6N/m2

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3 years ago
An 11.0 -W energy-efficient fluorescent lightbulb is designed to produce the same illumination as a conventional 40.0-W incandes
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The 40W bulb will be:

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Therefore, the amount that will be saved will be:

= $0.44 - $0.121

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