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a = (Vf - Vi)/t ; where distance d = [2(t)]/(4+t), t = 5secs, and Vi = 0
a = [(2t)/(4+t)]/t <---- working equation
a = {[2(5)]/9}/5 <---- cancel 5
a = 2/9 ft/s^2 <---- Answer
The speed of the object increases
Explanation:
We can answer this question by applying the work-energy theorem, which states that the work done on an object is equal to the change in kinetic energy of the object. Mathematically:

where
W is the work done on the object
are the final and initial kinetic energy of the object, respectively
m is the mass of the object
v is its final speed
u is its initial speed
In this case, the force does a positive amount of work on the object, so

This also implies that

And so

And therefore

which means that the speed of the object increases.
Learn more about work:
brainly.com/question/6763771
brainly.com/question/6443626
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Answer: p= m/v so 90kg/.075m^3 = 1,200
2a. .35 m 1.1 m and .015 m
2b. 35 cm x 110 cm x 1.5 cm = 5,775 cm^3 = 57.75 m^3
mass= pv
2700•57.75= 155,925 kg
mass= 155,925 kg
volume= 57.75 m^3
Explanation: physics
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