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postnew [5]
3 years ago
5

Pls help i have 2 hours to do this

Chemistry
1 answer:
Scilla [17]3 years ago
3 0
3ZnCl2 + 2Al → 2AlCl3 + 3Zn
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What type of air masses might make up the cold air mass in a cold front
Elena L [17]

Answer:

continental polar air masses

Explanation:

forms over Canada, move down from North Pole, bring bitterly cold and dry air to the northern United States during the winter.

4 0
3 years ago
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How many moles are 3.20 x102 formula units of calcium iodide?
DedPeter [7]

The number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

<h3>How to calculate number of moles?</h3>

The number of moles in the formula units of a substance is calculated by dividing the formula unit by Avogadro's number.

According to this question, 3.20 x 10² formula units are in calcium iodide. The number of moles is as follows:

no of moles = 3.20 x 10²² ÷ 6.02 × 10²³

no of moles = 0.53 × 10-¹

no of moles = 0.053 moles

Therefore, the number of moles in 3.20 x 10² formula units of calcium iodide is 0.053 moles.

Learn more about number of moles at: brainly.com/question/12513822

#SPJ6

3 0
2 years ago
Read 2 more answers
Hydrogen is manufactured on an industrial scale by this sequence of reactions: Write an equation that gives the overall equilibr
RideAnS [48]

The question is incomplete. The complete question is :

Hydrogen is manufactured on an industrial scale by this sequence of reactions:

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

The net reaction is  :

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

Write an equation that gives the overall equilibrium constant K in terms of the equilibrium constants K_1 and K_2. If you need to include any physical constants, be sure you use their standard symbols, which you'll find in the ALEKS Calculator.

Solution :

$CH_3(g) + H_2O(g) \rightleftharpoons CO(g) + 3H_2(g    ) \ \ \ \ \ \ \ \ \ \ K_1$

$K_1 = \frac{[CO][H_2]^3}{[CH_4][H_2O]}$     ...............(1)

$CO(g) + H_2O(g) \rightleftharpoons CO_2(g) + H_2(g) \ \ \ \ \ \ \ \ \ \ \ \  K_2$

$K_2 = \frac{[CO_2][H_2]}{[CO][H_2O]}$  ...................(2)

$CH_4(g) + 2H_2O(g) \rightleftharpoons CO_2(g) + 4H_2(g) \ \ \ \ \ \ \ \ \ K$

$K=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$

On multiplication of equation (1) and (2), we get

$K_1 \times K_2=\frac{[CO][H_2]^3}{[CH_4][H_2O]} \times \frac{[CO_2][H_2]}{[CO][H_2O]}$

$K_1K_2=\frac{[CO_2][H_2]^4}{[CH_4][H_2O]^2}$  .................(4)

Comparing equation (3) and equation (4), we get

$K=K_1K_2$

4 0
2 years ago
Anthracene is a yellow, crystalline solid found in coal tar. complete this structure for anthracene, c14h10, by adding bonds and
Assoli18 [71]

Anthracene is a polycyclic aromatic hydrocarbon with chemical formula C₁₄H₁₀. The number of fused rings in Anthracene are three in number. This compound is colorful and is used in the formation of different dyes due to its property of deloclization of pi electrons. All the carbon atoms in Anthracene are sp² hybridized with a trigonal planar structure hence, the Anthracene is planar in nature.

Number of Sigma Bonds:

                                         There are 26 sigma bonds (colored in Blue) in Anthracene among which 10 sigma bonds are between carbon and hydrogen atoms while the remaining are between the carbon atoms.

Number of Pi-Bonds:

                                  There are 7 pi bonds in Anthracene (colored in red). All pi bonds are present between carbon and carbon atoms.

Number of Electrons in Sigma Bonds:

                                                             As one sigma bond is formed by 2 electrons hence, 26 sigma bonds will be formed by 52 electrons.

Number of Electrons in Pi Bonds:

                                                       As one pi bond is formed by the side wise overlap of two p orbitals hence one pi bond is formed by two electrons so, 7 pi bonds will be formed by 14 electrons.

7 0
3 years ago
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A concentrated stock solution has molarity of 5 M. Calculate the volume (in mL) of the stock solution
Aleks [24]

Answer:

Explanation:

You have to calculate cuz you can`t count that much and he volume is 999.0031.

4 0
3 years ago
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