Answer:
Iron is being oxidized at the anode and water is acting as the electrolyte.
Explanation:
When iron is exposed to oxygen and water , the rusting of iron takes place.
<u>The reaction taking place at anode : Oxidation of iron.</u>
The reaction taking place at cathode : Reduction of oxygen in the air.
The overall reaction:
The rust that is hydrated iron(III) oxide can form iron(II) ions which can react further with oxygen.
Thus, from the above reactions ,
Iron is being oxidized at the anode and water is acting as the electrolyte.
There really isn't a difference if you think about it
First, we determine the energy required to melt one gram of ice. This is given by:
Energy = mass * latent heat of fusion
Energy = 1 g * 334 J/g
Energy = 334 J
Next, we use Planck's equation which is:
Energy = number of photons * Planck's constant * speed of light / wavelength
334 = n * 6.64 x 10⁻³⁴ * 3 x 10⁸ / 5.49 x 10⁻⁶
n = 9.20 x 10²¹
9.20 x 10²¹ photons need to be absorbed by the ice.
Answer: An imbalance of electric charge I the surface of an object
-electric charges that are stationary or at rest
-charges that build up on an object
