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Reika [66]
3 years ago
11

A student performs an experiment in measuring the period of a simple pendulum of known length 49.0 cm.He performed five trials a

nd measures the results(in second) to be :1.44,1.39,1.46,1.48,1.38.Calculate the % uncertainty to compare the measured value with the theoretical value.(Hint :Theoretical value=2I√l÷g,measured value=mean value)
Physics
1 answer:
Levart [38]3 years ago
4 0
Correct Answer is Bb
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Read 2 more answers
Air expands isentropically from 2.2 MPa and 77°C to 0.4 MPa. Calculate the ratio of the initial to the final speed of sound.
djyliett [7]

Answer:

The ratio of initial to final speed of sound is given as 1.28.

Explanation:

As per the thermodynamic relation of isentropic expansion

\frac{T_2}{T_1}=(\frac{P_2}{P_1})^{\frac{k-1}{k}}

Here

  • P_1 is the pressure at point 1 which is given as 2.2 MPa
  • T_1 is the temperature at point 1 which is given as 77 °C  or 273+77=350K
  • P_2 is the pressure at point 1 which is given as 0.4 MPa
  • T_2 is the temperature at point 2 which is to be calculated
  • k is the ratio of specific heats given as 1.4

Substituting values in the equation

                                      \frac{T_2}{350}=(\frac{0.4}{2.2})^{\frac{1.4-1}{1.4}}\\\frac{T_2}{350}=(0.18)^{0.2857}\\T_2=(0.18)^{0.2857} \times 350 \\T_2=0.61266 \times 350\\T_2=214.43 K

As speed of sound c is given as

c=\sqrt{kRT}

for initial to final values it is given as

\frac{c_i}{c_f}=\frac{\sqrt{k_1R_1T_1}}{\sqrt{k_2R_2T_2}}

As values of k and R is constant so the ratio is given as

\frac{c_i}{c_f}=\sqrt{\frac{T_1}{T_2}}

Substituting values give

\frac{c_i}{c_f}=\sqrt{\frac{350}{214.43}}\\\frac{c_i}{c_f}=\sqrt{1.63}}\\\frac{c_i}{c_f}=1.277  \approx 1.28

So the ratio of initial to final speed of sound is 1.28.

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Since the density of air decreases with an increase in temperature, but the bulk modulus B is nearly independent of temperature,
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To develop this problem it is necessary to apply the concept related to the speed of sound waves in fluids.

By definition we know that the speed would be given by

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\beta = Bulk modulus

\rho =Density of air

From the expression shown above we can realize that the speed of sound is <em>inversely proportional</em> to the fluid in which it is found, in this case the air. When the density increases, the speed of sound decreases and vice versa.

According to the statement then, if the density of the air decreases due to an increase in temperature, we can conclude that the speed of sound increases when the temperature increases. <u>They are directly proportional.</u>

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