Answer:
the velocity of the bullet-wood system after the collision is 2.48 m/s
Explanation:
Given;
mass of the bullet, m₀ = 20 g = 0.02 kg
velocity of the bullet, v₀ = 250 m/s
mass of the wood, m₁ = 2 kg
velocity of the wood, v₁ = 0
Let the velocity of the bullet-wood system after collision = v
Apply the principle of conservation of linear momentum to calculate the final velocity of the system;
Initial momentum = final momentum
m₀v₀ + m₁v₁ = v(m₀ + m₁)
0.02 x 250 + 2 x 0 = v(2 + 0.02)
5 + 0 = v(2.02)
5 = 2.02v
v = 5/2.02
v = 2.48 m/s
Therefore, the velocity of the bullet-wood system after the collision is 2.48 m/s
The phenomena<span> of </span>atmospheric<span> electricity are of three kinds. ..... In the Earth-</span>ionosphere cavity, the electric field<span> and conduction current in the lower </span>atmosphere<span> </span>
Answer:
The value is 
Explanation:
From the question we are told that
The power output from the sun is 
The average wavelength of each photon is 
Generally the energy of each photon emitted is mathematically represented as
Here h is the Plank's constant with value 
c is the speed of light with value 
So
=> 
Generally the number of photons emitted by the Sun in a second is mathematically represented as
=> 
=>
Definitely not me!!!! (unless it's magnetism or circuits)
You use less energy to provide the same service.
