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diamong [38]
3 years ago
14

You are on an alien planet where the names for substances and the units of measures are very unfamiliar. Nonetheless, you obtain

9 quibs of substance called skvarnick. You can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs. 12 sleps is equal to 9 quibs. If you have 9 quibs of skvarnick, how many sleps do you have? Round your answer to the nearest tenth (one decimal place). Type only the number; not the number and unit.
Chemistry
1 answer:
Margarita [4]3 years ago
3 0

Answer: 12


Explanation.


This problem was recently posted and deals with the conversion of units,so I give the same answer.


You need to convert the 9 quibs of skvarnick to sleps, to determine how many sleps you have.


The conversion of units is easily undertaken once you build your conversion factors.


Conversion factors are ratios (fractions) equivalent to one, which permits use the identity property of the multiplication to change one unit to a different equivalent one.


Remember that the identity property of multiplication states that any amount multiplied by 1 remains unchanged, i.e.

               a.1=a

Then, build your conversion factor from the definitions given:

  •    12 sleps is equal to 9 quibs.
  •    12 sleps = 9 quibs
  •    in virtue of the division property of equality, you can divide both sides by 12 sleps and get:

                                       1 = 12 sleps /  9 quibs ← conversion factor

Now you can multiply the amount 9 quibs by the conversion factor, which is equal to 1, to find the equivalent amount of sleps:


  •    identity property: 9 quibs = 9 quibs × 1
  •    substitution property: 9 quibs = 9 quibs ×  12 sleps/  9 quibs

You can see that the unit quibs appear in the numerator and the denominator so it cancels out, and the result will be in sleps.


So, all you have to do now is the operations with the numbers:

       9 quibs = (9 ×  12 / 9) sleps = 12 sleps ← answer

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Explanation:

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What is the molarity of solution that is 5.50 percentage by mass oxalic acid and has a density of 1.024 g/ml
Y_Kistochka [10]

Answer:

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

Explanation:

Mass percentage of oxalic acid = 5.50%

This means that in 100 grams of solution there are 5.50 grams of oxalic acid.

Mass of solution , m = 100

Volume of the solution = V

Density of the solution = d = 1.024 g/mL

V=\frac{m}{d}=\frac{100 g}{1.024 g/mL}=97.66mL

V = 97.66 mL = 0.09766 L

(1 mL = 0.001 L)

Moles of oxalic acid = \frac{5.50 g}{90 g/mol}=0.06111 mol

Molarity=\frac{\text{Moles of solute}}{\text{Volume of solution in L}}

The molarity of the solution :

=\frac{0.06111 mol}{0.09766  L}=0.6257M

0.6257 M is the molarity of solution that is 5.50 percentage by mass oxalic acid.

6 0
3 years ago
A 1.87 L aqueous solution of KOH contains 155 g of KOH . The solution has a density of 1.29 g/mL . Calculate the molarity ( M ),
Semenov [28]

Answer:        

[KOH] : 1.47 M

[KOH] : 1.22 m

[KOH]: 6.42 % mass percent.      

Explanation:

First of all we must determine the volume of solution. We have to work with the density

Density = mass / volume

1.29 g/ml = mass / 1870 ml

1.29 g/ml . 1870 ml = 2412.3

Now we must convert the mass to moles

155g / 56.1 g/ mol = 2.76 moles

Now we can calculate molarity

2.76 mol / 1.87 L = 1.47 M

To calculate molality we have to find out the mass of solvent

mass solute + mass solvent = mass solution

155 g + mass solvent = 2412.3 g

2412.3g - 155g = 2257.3g

We have to convert the 2257.3 g to kg

2257.3 g = 2.25 kg

molality = 2.76 moles / 2.25 kg = 1.22 m

To find out the % mass percentation, we have to calculate the mass of solute in 100 g of solution.

In 2412.3 g of solution we have 155 g of KOH

In 100 g of solution, we would have (100 . 155) / 2412.3 = 6.42 %mass percent.

7 0
3 years ago
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