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In-s [12.5K]
3 years ago
10

Match these items. 1. moles per liter of solution solute 2. spreading out Keq 3. substance being dissolved diffusion 4. general

equilibrium constant solvent 5. the substance doing the dissolving in a solution Ksp 6. solubility product constant molarity
Chemistry
1 answer:
Degger [83]3 years ago
8 0

Answer:

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq  

5. the substance doing the dissolving in a solution -  solvent

6. solubility product constant - Ksp

Explanation:

Number of moles of substance being dissolved in one liter of solution  is defined as molarity  

Solute is the substance which is dissolved and solvent is the substance into which the solute is dissolved. For example salt is solute and water is solvent.

Ksp defines the solubility product constant which indicates the equilibrium between a solid and solution and the number of ions of solid required to achieve this equilibrium.

Keq depicts the scenario where reactant and product concentrations are constant in a chemical reaction.  

Hence, the correct match is

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq  

5. the substance doing the dissolving in a solution -  solvent

6. solubility product constant - Ksp

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G determine the concentration of an hbr solution if a 45.00 ml aliquot of the solution yields 0.6485 g agbr when added to a solu
Sunny_sXe [5.5K]

The molecular weight of silver bromide (AgBr) is 187.77 g/mole. The presence of the ions in solution can be shown as- AgBr (insoluble) ⇄Ag^{+} + Br^{-1}.

45.00 mL of the aliquot contains 0.6485 g of AgBr. Thus 1000 mL of the aliquot contains \frac{0.6485}{45}×1000 = 14.411 gm-mole. Thus the solubility product K_{sp}of AgBr = [Ag^{+}]×Br^{-}.

Or, 5.0×10^{-13} = S^{2} (the given value of solubility product of AgBr is 5.0×10^{-13} and the charge of the both ions are same).

Thus S = (5.00×10^{-13})^{1/2} = 7.071×10^{-7} g/mL.

Thus the concentration of Br^{-1} or HBr is 7.071×10^{-7} g/mL.

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What volume of so2 is produced at 325 k and 1.35 atm when 15.0 grams of hcl reacts with excess k2so3?
vova2212 [387]
The volume of SO2 produced at 325k   is calculated as  below

calculate  the moles of SO2 produced  which  is calculated as follows

write the  reacting equation
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find the   moles  of  HCl  used
=mass/molar mass = 15g/ 36.5 g/mol =0.411 moles

by  use of mole ratio between  HCl to  SO2  which is  2:1 the moles of SO2 is therefore = 0.411 /2 =0.206  moles  of SO2

use the idea  gas  equation  to calculate the volume SO2
that is V=nRT/P  
where  n=0.206  moles
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