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In-s [12.5K]
4 years ago
10

Match these items. 1. moles per liter of solution solute 2. spreading out Keq 3. substance being dissolved diffusion 4. general

equilibrium constant solvent 5. the substance doing the dissolving in a solution Ksp 6. solubility product constant molarity
Chemistry
1 answer:
Degger [83]4 years ago
8 0

Answer:

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq  

5. the substance doing the dissolving in a solution -  solvent

6. solubility product constant - Ksp

Explanation:

Number of moles of substance being dissolved in one liter of solution  is defined as molarity  

Solute is the substance which is dissolved and solvent is the substance into which the solute is dissolved. For example salt is solute and water is solvent.

Ksp defines the solubility product constant which indicates the equilibrium between a solid and solution and the number of ions of solid required to achieve this equilibrium.

Keq depicts the scenario where reactant and product concentrations are constant in a chemical reaction.  

Hence, the correct match is

1. moles per liter of solution - Molarity

2. spreading out - diffusion

3. substance being dissolved- solute

4. general equilibrium constant - Keq  

5. the substance doing the dissolving in a solution -  solvent

6. solubility product constant - Ksp

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Answer: Water inside the seed coat creating a pushing force, breaking the seed coat.

Explanation:

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8 0
3 years ago
Calculate the solubility product constant, Ksp, of lead(II) chloride, PbCl2, which has a
V125BC [204]

Answer:

0.0159m

Explanation:

9 M

Explanation:

Lead(II) chloride,  

PbCl

2

, is an insoluble ionic compound, which means that it does not dissociate completely in lead(II) cations and chloride anions when placed in aqueous solution.

Instead of dissociating completely, an equilibrium rection governed by the solubility product constant,  

K

sp

, will be established between the solid lead(II) chloride and the dissolved ions.

PbCl

2(s]

⇌

Pb

2

+

(aq]

+

2

Cl

−

(aq]

Now, the molar solubility of the compound,  

s

, represents the number of moles of lead(II) chloride that will dissolve in aqueous solution at a particular temperature.

Notice that every mole of lead(II) chloride will produce  

1

mole of lead(II) cations and  

2

moles of chloride anions. Use an ICE table to find the molar solubility of the solid

 

PbCl

2(s]

 

⇌

 

Pb

2

+

(aq]

 

+

 

2

Cl

−

(aq]

I

 

 

 

−

 

 

 

 

 

0

 

 

 

 

 

0

C

 

 

x

−

 

 

 

 

(+s)

 

 

 

 

(

+

2

s

)

E

 

 

x

−

 

 

 

 

 

s

 

 

 

 

 

2

s

By definition, the solubility product constant will be equal to

K

sp

=

[

Pb

2

+

]

⋅

[

Cl

−

]

2

K

sp

=

s

⋅

(

2

s

)

2

=

s

3

This means that the molar solubility of lead(II) chloride will be

4

s

3

=

1.6

⋅

10

−

5

⇒

s

=  √ 1.6 4 ⋅ 10 − 5  = 0.0159 M

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