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3 years ago

Can you write a quadratic equation with the solutions of 0 and 9

1 answer:

6 0

That is easy, lets get two factors with those solutions:
x(x - 9) = 0
that equation is solved if x = 0 because one factor is zero, and if x = 9 as well for the same reason (try it!), so the equation is:
<span>x(x - 9) = 0
</span>x^2 - 9x = 0

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To estimate the length of the lake, caleb starts at one end of the lake and walk 95m. He then turns a 60° angle and walks on a n

aivan3 [116]

Answer:

Length of the lake is 97.30 m

Step-by-step explanation:

We have given Caleb starts at one end of the lake and walk 95 m

So $d_1=95m$

And then he turns at an angle of 60°

So $\Theta =60^{\circ}$ and then again walk 8 m

So $d_2=8m$

We have to fond the total length of the lake , that is d

Total length of the lake is given by $d=\sqrt{d_1^2+d_2^2+2d_1d_2cos\Theta }=\sqrt{95^2+8^2+2\times 95\times 8\times cos60^{\circ}}=97.30m$

So length of the lake is 97.30 m

3 0

3 years ago

Is 25% of a whole always the same amount ?

wel

Answer:

Not, will be the same proportion but the amount vary depending the specific case.

Best regards

6 0

4 years ago

Read 2 more answers

What is the first operation you start with when solving

Alex17521 [72]

The correct answer is B addition
You will add 4 to both sides then the equation will be 2x=5

5 0

3 years ago

Help plz:)))I’ll mark u Brainliest

goldfiish [28.3K]

Answer:

11, 21, 31

Step-by-step explanation:

In a triangle with side lengths $a$ , $b$ , and $c$ , any two sides must have a sum larger than the third.

Using this rule, the possible side lengths out of these choices that could form a triangle are:

21,

11,

8 0

3 years ago

Find the inverse of the function. State any restrictions on the domain.<br><br> f(x) = x^2 + 9

Bogdan [553]

The function is not invertible if you think of it as

$f:\mathbb{R}\to\mathbb{R}$

because it is not injective: $f(x)=f(-x)$

So, if we restrict the domain to the positive numbers only:

$f:\mathbb{R^+}\to\mathbb{R}$

Note that the range is actually $[9,\infty)$ , so we can be more precise and write

$f:\mathbb{R^+}\to[9,\infty)$

To find the inverse, we solve the expression for x:

$y=x^2+9 \iff y-9=x^2 \iff x=\pm\sqrt{y-9}$

But since we restricted to positive values of x, the inverse is

$x=\sqrt{y-9}$

8 0

3 years ago