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erik [133]
4 years ago
11

Which machine would be an alternative to lifting a crate with a pulley?

Physics
2 answers:
lana66690 [7]4 years ago
6 0
B because the ramp has the most mobility

igomit [66]4 years ago
5 0

Answer: Option (b) is the correct answer.

Explanation:

A crate will be difficult to carry or pull when we take it through doorstop. Whereas ax and screw will not be of much use for carrying the crate.

Therefore, we can conclude that out of the given options ramp would be an alternative to lifting a crate with a pulley as it will help in easily moving the crate form one point to another.

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How much force is needed to stop a 4000 kg truck moving at 8 m/s in 0 2 seconds?​
maksim [4K]

Answer:

32000 N

Explanation:

Force Calculater

8 0
3 years ago
Which of the following is a characteristic of inner planets? (2 points)
Dmitry_Shevchenko [17]
"Inner" planets are usually considered to be Mercury, Venus,
Earth, and Mars.

A).  No.  None of these planets has any substantial amount of hydrogen
or helium in its atmosphere.

B).  No.  Mercury and Venus have no moons at all, and Earth and Mars
have only three moons total between them.

C).  No.  Not sure what this means, but the "ground" seems like a pretty fair
land-atmosphere interface, and Venus, Earth, and Mars have a lot of that.

D).  Yes.  All four of them have it.
3 0
4 years ago
Read 2 more answers
Which of the following do cutoffs form in a meandering river
mrs_skeptik [129]

Answer: An oxbow lake forms after there has been deposition of sediment, by the new cutoff channel flowing adjacent to it, at the entrances of the abandoned bend; this seals the bend off from the rest of the river.

8 0
4 years ago
What is the difference between charging by contact and charging by induction in terms of electron transfer.
Veronika [31]

Answer:

the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch

Explanation:

There are three methods of charging an object:

- Charging by friction: this is done by rubbing an object against another object. An example is when a plastic rod is rubbed with a wool cloth. When this is done, electrons are transferred from the wool to the rod, so both objects remain charged at the end of the process

- Charging by contact: this is done by putting in contact a charged object with a neutral, conducting object. In this case, the charges are transferred from the charged object to the neutral object; at the end of the process, the neutral object will also have a net electric charge, so it will be also charged.

- Charging by induction: in this case, we take a charged object, and a neutral object, and we place the two objects close to each other, but without touching. Let's assume that the charged object is negatively charged: in this case, the positive charges in the neutral object are attracted towards the negative charges of the charged object, while the negative charges of the neutral object are repelled away. As a result, the positive and negative charges in the neutral object split apart. If the object is connected to the ground, then negative charges move away, so the neutral object will remain positively charged.

Therefore, the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch.

5 0
3 years ago
A neutron consists of one "up" quark of charge +2e/3 and two "down" quarks each having charge -e/3. If we assume that the down q
Anon25 [30]

Answer:

The magnitude of the electrostatic force is 120.85 N

Explanation:

We can use Coulomb's law to find the electrostatic force between the down quarks.

In scalar form, Coulomb's law states that for charges q_1 and q_2 separated by a distance d, the magnitude of the electrostatic force F between them is:

F = k \frac{|q_1q_2|}{d^2}

where k is Coulomb's constant.

Taking the values:

d = 4.6 \ 10^{-15} m

q_1 = q_2 = - \frac{e}{3} = - \frac{1.6 \ 10^{-19} \ C}{3}

and knowing the value of the Coulomb's constant:

k = 8.99 \ 10 ^{9} \frac{N m^2}{C^2}

Taking all this in consideration:

F = 8.99 \ 10 ^{9} \frac{N m^2}{C^2} \frac{ (- \frac{1.6 \ 10^{-19} \ C}{3} ) ^2}{(4.6 \ 10^{-15} m)^2}

F = 120.85  \ N

8 0
3 years ago
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