Answer:
I would say A. I'm no expert, but it can't be C obviously, and I think wind would hit all of it, wearing off the top as well like the great pyramids. B would be my next choice, but A i think would be best.
Let's write the equation

According to law of conservation of mass .
- Mass of products=Mass of reactants
Let required value be x




The total number of elements that one particular element can bond to can be determined by simply drawing the Lewis structure of the element.
Place the chemical symbol
Then look at the group number = valence electrons
Distribute the valence electrons around the atom.
C = 4 bonds
N = 3 bonds
O = 2 bonds
<h3>i think its help</h3><h3>iron ( III )</h3><h3>oxide ( Fe,O )</h3>